2. Draw shear force and bending moment diagrams for the beam shown in figure. 50 kN/m 20 kN/m A D 2 m 2 m 2 m RA Ro 3. Relation between load, shear and moment: Please solve according to the exporters of a typical solution. We will discuss the relations existing between the loads, shears and bendir moments in any beam. Theses relations provide a method of constructing she and moment diagrams without writing shear and moment equations. The beam shown in figure (1) is assumed to carry any general loading. The free body diagram W (N/m) of segment of this beam of length (dx) is shown but f wdx - is the summation of area between (x, and x;) in figure (2). V, -v, = AV = (area) similarly (2) EF, -0>V+wdx-(V+d)-0 --Intensity of load (N/m) dV = wde EM, 0 M+Vdx + (wex) - (M+ dM) =0 M, - M, - AM = (area ) dV (de ) Where: ero dr (slope of shear dingram) 2. dM=Vde for (dV = wdx) we can integrating dM (slope of moment diagram)

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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2. Draw shear force and bending moment diagrams for the beam shown in figure.
50 kN/m
20 kN/m
D
to
2 m
2 m
2 m
RA
Ro
3. Relation between load, shear and moment:
Please solve according to
the exporters of a typícal
solution.
We will discuss the relations existing between the loads, shears and bendin
moments in any beam. Theses relations provide a method of constructing she
and moment diagrams without writing shear and moment equations.
The beam shown in figure (1) is assumed to carry any general loading.
The free body diagram
jar - jute
W Nm)
of segment of this beam
of length (dx) is shown
in figure (2).
wtx = is the summation of area between (x) and x;)
but
V, -V, = AV = (area)
similarly
(1)
(2)
EF, -0>V+ wdx-(V+dV)=0
-Intensity of load (N/m)
. dV = wdx
EM, 0= M+Vdx + (wcbx) - (M + dM) =0
dM =
M, - M, - AM = (area )
AP
dx
(de)
~zero
2
. dM=Vde
Where:
(slope of shear diagram)
.V =
INP
(slope of moment diagram)
for (dV = wdx)
we can integrating
de
Transcribed Image Text:2. Draw shear force and bending moment diagrams for the beam shown in figure. 50 kN/m 20 kN/m D to 2 m 2 m 2 m RA Ro 3. Relation between load, shear and moment: Please solve according to the exporters of a typícal solution. We will discuss the relations existing between the loads, shears and bendin moments in any beam. Theses relations provide a method of constructing she and moment diagrams without writing shear and moment equations. The beam shown in figure (1) is assumed to carry any general loading. The free body diagram jar - jute W Nm) of segment of this beam of length (dx) is shown in figure (2). wtx = is the summation of area between (x) and x;) but V, -V, = AV = (area) similarly (1) (2) EF, -0>V+ wdx-(V+dV)=0 -Intensity of load (N/m) . dV = wdx EM, 0= M+Vdx + (wcbx) - (M + dM) =0 dM = M, - M, - AM = (area ) AP dx (de) ~zero 2 . dM=Vde Where: (slope of shear diagram) .V = INP (slope of moment diagram) for (dV = wdx) we can integrating de
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