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= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution

= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution
Transcribed Image Text:= 40.6 The heat of vaporization when 1 mol of water boils at 100 °C is 40.6kJ/mol (AHvap= kJ/mol). Calculate AS for when 1 mole of water evaporates at 100.°C. H₂O(l) → H₂O(g). sys a. -109 J/K b. + 406 J/K c. +109 J/K d. +11.2 J/K e. -12 J/K Give clear handwritten Solution
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