7H5O2 = 160.21 C7H8O2 = 122 Density: C7H8 = 0.87 g/mL KMnO4 = 2.7 g/mL KC7H5O2 = 1.5 g/mL C7H8O2 = 1.27 g/mL If 1 mL of toluene and 4 mL of 50% w/v potassium permanganate solution are used to synthesize the benzoic acid in a reflux set-up, calculate the theoretical yield of benzoic acid. Show your complete solution and underline your final answer.
7H5O2 = 160.21 C7H8O2 = 122 Density: C7H8 = 0.87 g/mL KMnO4 = 2.7 g/mL KC7H5O2 = 1.5 g/mL C7H8O2 = 1.27 g/mL If 1 mL of toluene and 4 mL of 50% w/v potassium permanganate solution are used to synthesize the benzoic acid in a reflux set-up, calculate the theoretical yield of benzoic acid. Show your complete solution and underline your final answer.
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter23: Carbon: Not Just Another Element
Section: Chapter Questions
Problem 106IL
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Question
Given the chemical equation in the synthesis of benzoic acid from toluene and potassium permanganate:
C7H8(I) + 2KMnO4(aq) → KC7H5O2 + 2MnO2 (s) + KOH (aq) + H2O (I)
KC2H5O2 (aq) + HCl (aq) → C7H8O2 (s) + KCl (aq)
MW: C7H8 = 92.14
KMnO4 = 158.03
MnO2 = 86.94
KC7H5O2 = 160.21
C7H8O2 = 122
Density: C7H8 = 0.87 g/mL
KMnO4 = 2.7 g/mL
KC7H5O2 = 1.5 g/mL
C7H8O2 = 1.27 g/mL
If 1 mL of toluene and 4 mL of 50% w/v potassium permanganate solution are used to synthesize the benzoic acid in a reflux set-up, calculate the theoretical yield of benzoic acid. Show your complete solution and underline your final answer.
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