A 4 m 24 kN 4 m D E 4 m B 12 kN C
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Determine the vertical displacement of joint C. Assume the members are pin connected at their end points. Take A=200mm2 and E=200GPa for each member. Use the method of virtual work.
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- A= 63.04 cM², bF = 100 wm, tF = IS-3 wm For ISMC 400 tw = 8.6 mm, Ixx = 15123.4 cm4 For ISA 1asx75X 10 Iyy e 8t-6 an, Crr = 4.04 cm Ivy = s06.3 cnt, cuy = 243 cM ISA 125X TSX10 A = 19.02 Cu? Ixx = 300. 3 CM", Cy y = 1. 76 cm ISMC 400 For the builtup section shown in the figure, provided are the details of the individual structural properties. Find: [ Select ] The x bar from the bottom of the overall figure [ Select] the centroidal MOI lyyThe square root ratio of the area of the portion of the supporting surface to the area of steel concentrically bearing on concrete support(v(A2/A1) ) is ranging between 25/(A2/A1) < 3 O 1sv(A2/A1) <2 O 4Structural Analysis: Solve the F4-5Determine the design strength of a T- Beam given the following data: bf = 700 mm bw = 300 mm hf = 100 mm d = 500 mm %3D fe' = 21 MPa fy = 414 MPa As: 5- 20 mm dia.L1 L2 H2 D. B H1A 10 m high 150UC30 steel column is fixed at its base and restrained to move laterally in the x direction at the top and at mid-height. Determine the allowable eccentric force P that can be applied without causing the column to either buckle or yield. Adopt a safety factor of 2 against buckling and yielding. Hint: You may choose to use a computer program to help solve the arising iterative equation. Alternatively, you may choose to not solve the equation at all and check the criticality of a requirement by simple substitution.a = 1 m b = 5 m c = 6 m d=1m e = 3 m P₁ = 34 kPa P₂ = 46 kPa P3 = 57 kPa P4 = 26 kPa P5 = 6 kPa (kN \m². (kN m² kN P6 = 117 kPa kN - 1m² kNy \m² kN P₁ P4 a 4. Ry= 5. R= P₂ b P6 KN KN KN B P5 P₂ The L-shaped retaining wall shown retains soil on the right side and water on the left side is to be analyzed. Fluid pressure is shown with bottom pressure equal to P₁ acting on the left side of the wall. Soil pressure is also shown with bottom pressures P2 and P3, acting on the right sides of the wall. Trapezoidal uplift pressure due to seepage is acting at the bottom of the wall with pressure P4 on the side of the water (on point A) and Ps on point B. The horizontal part of the wall is also subjected to the weight of the soil above it with magnitude P6. The wall is made of concrete with unit weight 23.5 kN/m³. Assume 1 meter width for the analysis and include the self-weight of the structure. P3 Calculate the magnitude and location of the resultant of uplift pressure. 1. Magnitude = kN 2.…Situation 4: A W12x106 simply supported beam carries a uniformly distributed load. The properties of the section relevant to the problem are as follow: Use A50 steel and Cb - 1.14 d - 328 mm bf-310 mm tf = 25.1 mm tw = 15.5 mm kdes - 40.4 mm ry - 79.0 mm lx = 388 x 10^6 mm^4 ly - 125 x 10^6 mm^4 Sx - 2380 x 10^3 mm^3 Zx=2690 x 10^3 mm^3 J-3800 x 10^3 mm^3 Cw=2870 x 10^9 mm^6 1. Which of the following nearly gives the Design Strength Moment (LRFD) if the span of the beam is 2.5m? 878 KN-m 793 KN-m 836 KN-m 811 KN mPROBLEM The centroid of the T-section shown is 2.5 inches above the base. What should be the value of b to satisfy this condition? Input value only without the unit, 1" 8" 1" b6 6a 6b 6c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is W 6 x 20 however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? Use: Fy=248 MPa: E=200,000 MPa Designation W8 x 24 W8 x 21 Weight Ag (mm2) 3787 36 31 width mm kg/m d (depth) 30 157.48 152.91 9.27 W6 x 20 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) W8 x 28 42 204.72 165.99 11.81 5323 4568 201.42 164.97 10.16 3974 210.31 133.86 flange bf thickness tf Web 10.16 thickness tw 6.60 Elastic Properties mm 4 Ix x 106 7.24 6.22 6.35 17 41 34 31 mm 3 Sxx 103 220 398 342 298 mm rx 67.56 87.63 86.87 88.65 mm 4 lyx 106 6 9 8 4 mm 3 Syx 106 72 109 92 61 mm ry 38.10244 41.15 40.89 32 Plastic properties. mm 3 Zx x 103 244 446 380 334 mm 3 Zyx 103 110 166 140 93…The top chord of a bridge truss has an actual length of 5.0 m and cross-section as shown in Fig. Determine the service compressive load carrying capacity of member if the structural steel is of grade Fe 410 y X 250 mm 123mm 80 mm 100mm y = 23 mm ; yy Iyy = 211 x 104 t = 7.2 mm ; t = 14.1 mm C XX y For ISMC 250@ 30.6 kg/m A = 3900 mm² h = 250 mm; b= 80 mm λ = 3880 × 104 mm¹ mm4 f Cover plate 260 × 8 cd 80 mm X -ISMC 250 50 60 70 183 168 152 Lacingfind out F, KN F23 f13 f16SEE MORE QUESTIONS