A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0310 nm. After the collision, the electron moves at an angle a below the +x- axis, while the photon moves at an angle = 81.3° above the +x-axis. (For the purpose of this exercise, assume that the electron is traveling slow enough that the non-relativistic relationship between momentum and velocity can be used.) (a) What is the angle a (in degrees)? 47.21 What is the shift in wavelength of the photon due to the scattering? How can you use momentum conservation in the horizontal and vertical directions to determine the angle? ° counterclockwise from the +x-axis (b) Determine the speed of the electron (in m/s). m/s
A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0310 nm. After the collision, the electron moves at an angle a below the +x- axis, while the photon moves at an angle = 81.3° above the +x-axis. (For the purpose of this exercise, assume that the electron is traveling slow enough that the non-relativistic relationship between momentum and velocity can be used.) (a) What is the angle a (in degrees)? 47.21 What is the shift in wavelength of the photon due to the scattering? How can you use momentum conservation in the horizontal and vertical directions to determine the angle? ° counterclockwise from the +x-axis (b) Determine the speed of the electron (in m/s). m/s
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![A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0310 nm. After the collision, the electron moves at an angle a below the +x-
axis, while the photon moves at an angle = 81.3° above the +x-axis. (For the purpose of this exercise, assume that the electron is traveling slow enough that the non-relativistic relationship
between momentum and velocity can be used.)
(a) What is the angle a (in degrees)?
47.21
What is the shift in wavelength of the photon due to the scattering? How can you use momentum conservation in the horizontal and vertical directions to determine the angle? ° counterclockwise
from the +x-axis
(b) Determine the speed of the electron (in m/s).
m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd87a8261-32e8-414d-a356-2455d9f30f2c%2F6de5928f-606e-4118-8a35-628b6d0d5c37%2Fz1uqskb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0310 nm. After the collision, the electron moves at an angle a below the +x-
axis, while the photon moves at an angle = 81.3° above the +x-axis. (For the purpose of this exercise, assume that the electron is traveling slow enough that the non-relativistic relationship
between momentum and velocity can be used.)
(a) What is the angle a (in degrees)?
47.21
What is the shift in wavelength of the photon due to the scattering? How can you use momentum conservation in the horizontal and vertical directions to determine the angle? ° counterclockwise
from the +x-axis
(b) Determine the speed of the electron (in m/s).
m/s
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