A solution is prepared by adding 0.18 mole of Ni(NH3) 6 Cl₂ to 0.50 L of 2.0 M NH3. Calculate [Ni(NH3)²+] and Ni²+ in this solution. 2+ Koverall for 2+ Ni (NH3)²+ is 5.5 × 108. That is, 5.5 × 108 [Ni²+] = = Ni (NH3)2+ [Ni²+ ][NH® for the overall reaction 2+ Ni²+ (aq) + 6NH3 (aq) — Ni (NH3)6²+ (aq) 2+ [Ni (NH3)6 ²+] = M M

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Chapter20: Transition Metals And Coordination Chemistry
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A solution is prepared by adding 0.18 mole of
Ni (NH3)6 Cl2 to 0.50 L of 2.0 M
NH3. Calculate
[Ni (NH3)6 ²+ ] and
[Ni²+] in this solution.
Koverall for
2+
Ni (NH3)6 is
5.5 × 108. That is,
5.5 x 108 -
for the overall reaction
Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)²+ (aq)
Ni (NH3)6²+]
[N₁²+] =
2+
[Ni (NH3),²+]
[Ni2+ ] [NH3]®
16
=
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Transcribed Image Text:A solution is prepared by adding 0.18 mole of Ni (NH3)6 Cl2 to 0.50 L of 2.0 M NH3. Calculate [Ni (NH3)6 ²+ ] and [Ni²+] in this solution. Koverall for 2+ Ni (NH3)6 is 5.5 × 108. That is, 5.5 x 108 - for the overall reaction Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)²+ (aq) Ni (NH3)6²+] [N₁²+] = 2+ [Ni (NH3),²+] [Ni2+ ] [NH3]® 16 = Submit Answer M M Try Another Version 1 item attempt remaining
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