(b) At 100° C, the keq for the Haber process is 4.51 x 10°5: N₂ + 3H₁₂ 2 NH3 Consider the following reaction conditions and determine if the system is at equilibrium. If not, indicate the direction in which the reaction must proceed to establish equilibrium (i) PNH3 = 105 atm, PN2 = 35 atm and P2 = 495 atm (ii) PNH3 = 35 atm, PN2 = 0 atm and PH₂ = 595 atm (iii) PNH3 = 26 atm, PN2 = 202 atm and PH2 = 42 atm (iv) PNH = 105 atm, PN2 = 5 atm and PH₂ = 55 atm

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 7QRT
icon
Related questions
Question
  • At 100° C, the Keq for the Haber process is 4.51 x 10-5:

N2 + 3 H2  ------>  2 NH3

Consider the following reaction conditions and determine if the system is at equilibrium. If not, indicate the direction in which the reaction must proceed to establish equilibrium

  • pNH3 = 105 atm, pN2 = 35 atm and pH2 = 495 atm
  • pNH3 = 35 atm, pN2 = 0 atm and pH2 = 595 atm
  • pNH3 = 26 atm, pN2 = 202 atm and pH2 = 42 atm
  • pNH3 = 105 atm, pN2 = 5 atm and pH2 = 55 atm

 

(b) At 100° C, the keq for the Haber process is 4.51 x 10°5:
N₂ + 3H₁₂
2 NH3
Consider the following reaction conditions and determine if the system is at equilibrium.
If not, indicate the direction in which the reaction must proceed to establish equilibrium
(i)
PNH3 = 105 atm, PN2 = 35 atm and P2 = 495 atm
(ii)
PNH3 = 35 atm, PN2 = 0 atm and PH₂ = 595 atm
(iii)
PNH3 = 26 atm, PN2 = 202 atm and PH2 = 42 atm
(iv)
PNH = 105 atm, PN2 = 5 atm and PH₂ = 55 atm
Transcribed Image Text:(b) At 100° C, the keq for the Haber process is 4.51 x 10°5: N₂ + 3H₁₂ 2 NH3 Consider the following reaction conditions and determine if the system is at equilibrium. If not, indicate the direction in which the reaction must proceed to establish equilibrium (i) PNH3 = 105 atm, PN2 = 35 atm and P2 = 495 atm (ii) PNH3 = 35 atm, PN2 = 0 atm and PH₂ = 595 atm (iii) PNH3 = 26 atm, PN2 = 202 atm and PH2 = 42 atm (iv) PNH = 105 atm, PN2 = 5 atm and PH₂ = 55 atm
AI-Generated Solution
AI-generated content may present inaccurate or offensive content that does not represent bartleby’s views.
steps

Unlock instant AI solutions

Tap the button
to generate a solution

Similar questions
Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781337398909
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781285199030
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning