Assume that two pigments, red and bluc, mix to give the normal purple color of petunia petals. Separate biochemical pathways synthesize the two pigments, as shown in pathways I and Il in the accompanying diagram. "White" refers to compounds that are not pigments (total lack of pigment results in a white petal). Red pigment forms from a yellow intermediate that is normally at a concentration loo kow to color petals. Bluc mixed with yellow makes green. Assume that no mutations are lethal. Pathway I.. White Blue Pathway I White, Yellow Red Pathway II White, White, A third pathway, whose compoundk do not contribute pelal pigmentation, normally docs not allfect the bluc and red pathways. However, if one of its intermediates (white3) should build up in concentration, it can be converted into the ycllow intermediate of the red pathway. In the diagram, the letiers A through E represent enzymes. The enzymes' correspoonding genes, all of which are unlinked, may be symbolized by the same letters. Assume that wikl-type alleles are dominant and encode enzyme function, and that recessive alleles result in a lack of cnzyme function. Deduce which combinations of truc-breeding parental genotypes could be crossed to produce F2 progeny in these ratios. 9 purple : 3 green : 4 bluc O A/A ; bb x ala ; B/B O ala ; b x AIA ; b O A/A ; bb x AIA ; b A/A ; B/B x ala ; bb 9 purple : 3 red :3 bluc :1 white O A/A ; FEx ala ; ele O A/A ; ele x ala ; EE O A/A ; FE x ala ; E O A/A ; ele x ala ; ele 13 purple : 3 bluc A/A ; dd x ala ; DD O A/A ; IMD x ala ; IMD O AA ; did x ala ; did A/A ; DVD x ala ; did 9 purple : 3 red : 3 green : 1 yellow O B/B ; EE x R/B ; ele O B/B ; EE x bb; ele b/b ; EE x B/B ; EE B/B ; ele x b/b ; EE
Assume that two pigments, red and bluc, mix to give the normal purple color of petunia petals. Separate biochemical pathways synthesize the two pigments, as shown in pathways I and Il in the accompanying diagram. "White" refers to compounds that are not pigments (total lack of pigment results in a white petal). Red pigment forms from a yellow intermediate that is normally at a concentration loo kow to color petals. Bluc mixed with yellow makes green. Assume that no mutations are lethal. Pathway I.. White Blue Pathway I White, Yellow Red Pathway II White, White, A third pathway, whose compoundk do not contribute pelal pigmentation, normally docs not allfect the bluc and red pathways. However, if one of its intermediates (white3) should build up in concentration, it can be converted into the ycllow intermediate of the red pathway. In the diagram, the letiers A through E represent enzymes. The enzymes' correspoonding genes, all of which are unlinked, may be symbolized by the same letters. Assume that wikl-type alleles are dominant and encode enzyme function, and that recessive alleles result in a lack of cnzyme function. Deduce which combinations of truc-breeding parental genotypes could be crossed to produce F2 progeny in these ratios. 9 purple : 3 green : 4 bluc O A/A ; bb x ala ; B/B O ala ; b x AIA ; b O A/A ; bb x AIA ; b A/A ; B/B x ala ; bb 9 purple : 3 red :3 bluc :1 white O A/A ; FEx ala ; ele O A/A ; ele x ala ; EE O A/A ; FE x ala ; E O A/A ; ele x ala ; ele 13 purple : 3 bluc A/A ; dd x ala ; DD O A/A ; IMD x ala ; IMD O AA ; did x ala ; did A/A ; DVD x ala ; did 9 purple : 3 red : 3 green : 1 yellow O B/B ; EE x R/B ; ele O B/B ; EE x bb; ele b/b ; EE x B/B ; EE B/B ; ele x b/b ; EE
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter11: Genome Alterations: Mutation And Epigenetics
Section: Chapter Questions
Problem 8QP: Bruce Ames and his colleagues have pointed out that although detailed toxicological analysis has...
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