d. A plastic and liquid test was conducted to determine the plasticity of a clay soil. The mass of water and dry soil from plastic limit test are 2.65 g and 12.35 g respectively. The table below gives the test result of liquid limit tests conducted in using fall cone method. Determine the level of plasticity of the clay soil. Moisture content (%) 83.01 86.28 90.69 Penetration (d) 10.85 14.68 18.11 90.99 97.82 101.06 112.32 18.39 22.79 23.44 30.69
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- In falling head permeability test the initial head was 350 mm and the final head was 50 mm. The cross-sectional area of the burette was 200 mm2. The sample was 50 mm in diameter and 100 mm long. If the test took 8 hours and 45 minutes, what was the coefficient of permeability of the soil in m/s? a.7.15 x 10-7 m/s b.6.29 x 10-7 m/s c.7.89 x 10-7 m/s d.8.78 x 10-7 m/s e.5.69 x 10-7 m/s1. During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following results from a clayey soil. Liquid limit tests: Number of Moisture blows, N content (%) 14 38.4 16 36.5 20 33.1 28 270 Plastic limit tests: Students conducted two trials and found that PL = 172% for the first trial and PL = 17.8% for the second trial. a. Draw the flow curve and obtain the liquid limit. b. What is the plasticity index of the soil? Use an average value of PL from the two plastic limit trails.A cylindrical soil sample 50 mm in diameter and 200 mm in height is used as thepermeameter in a falling head permeability test setup. In one minute of observation, thehydraulic head in the 10 mm diameter standpipe through which test water went reducedfrom 900mm to 500 mm. During that time, 1.5 liters of water were collected in the graduate. Calculate the soil sample's permeability coefficient in cm/s.
- Afalling-head permeability test is performed on a fine-grained soil. The soil sample has a length of 120 mm and a cross-sectional area of 600 mm2. The water in the standpipe flowing into the soil is 0.60 m above the top of the sample at the start of the test. It falls 50 mm in 30 minutes. The standpipe has a cross-sectional area of 200 mm2. (a) Make a sketch of the described conditions. (b) What is the coefficient of permeability in millimeters per second? (c) What is the coefficient of permeability in feet per minute? (d) On the basis of the calculated value for khyd, what is the probable soil type?Problem 1: During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following results from a clayey soil. Liquid limit tests: Number of Moisture blows, N content (%) 14 38.4 16 36.5 20 33.1 28 27.0 Plastic limit tests: Students conducted two trials and found that PL= 17.2% for the 1st trial and PL = 17.8% for the second trial. Draw the flow curve and obtain the liquid limit. What is the plasticity index of the soil? (Hint: Use an average value of PL) Determine the flow index. Determine the liquidity index of the soil if the in-situ moisture content is 21%, and comment on the probable engineering behavior of this soil.A constant head permeability test is performed on soil that is 2 cm x 2 cm square, and 2.5cm long. The head difference applied during the test is 20 cm and 7 cm3 is collected over a time of 100 sec. Provide step by step solution. a) Compute the permeability based on these test conditions and results. b) A falling head test is conducted on the same soil specimen at the same time (t1 – t2 = 100 sec), and the standpipe diameter is 0.8 cm. If the average head during the test should be 18 cm, what are h1 and h2 values, provide step by step solution solving h1 and h2 values.
- Don't attempt wrong i will downvote.....A cylindrical soil sample, 7.3 cm in diameter and 16.8 cm in height, is tested in a constant-head permeability apparatus. A constant head of 75 cm is maintained during the test. After 1 minute of testing, a total of 945.7 gm of water was collected. The temperature was 20 oC. The void ratio of the soil was 0.43. Calculate the following: 1. The hydraulic gradient 2. The flow rate 3. The discharge velocity 4. The seepage force per unit volume 5. The coefficient of permeabilityIn falling head permeability test the initial head was 350 mm and the final head was 60 mm. The cross-sectional area of the burette was 200 mm2. The sample was 50 mm in diameter and 105 mm long. If the test took 8 hours and 30 minutes, what was the coefficient of permeability of the soil in m/s?soil mechanics Q1- he mass of a moist soil sample collected from the field is 465 grams, and its oven dry mass is 05.76 grams. The specific gravity of the soil solids was determined in the laboratoryo be 2.68. If the void ratio of the soil in the natural state is 0.83, find the following: a. The moist density of the soil in the field in kN/m³ b. The dry density of the soil in the field in kN/m³ c. The mass of water, in kilograms, to be added to the soil for saturation
- Results from a liquid limit test conducted on a soil are given below. Number of blows, N 12 19 27 37 Moisture content (%) 35.2 29.5 25.4 21 a. Determine the liquid limit of the soil. b. If it is known that the PI = 6.5, what would be the plastic limit of the soil? C. Determine the liquidity index of the soil if w = 23.8% in situPermeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio (e) 0.65 1.02 Temperature °℃ 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10-¹ At 40° C, n = 6.54 × 10-¹ g sec/cm² and p $0.997 g/cm³ = = 0.992 g/cm³Permeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio Temperature °C (e) 0.65 1.02 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10¹ At 40° C, n = 6.54 × 10 g sec/cm² and p 8 0.997 g/cm³ = 0.992 g/cm³