eaction: ZnO (s) + C (graphite) = Zn (s) + CO (g) Heat of fusion of zinc at melting point (420°C) = 1.74 kcal/mole and heat of vaporation of zinc at boiling point (907°C) = 27.3 kcal/mole. Calculate the change in ree energy for the reaction at 907 °C. iven that: Material S° 298 (cal/deg/mole) AH°298 (kcal/mole) C, (cal/deg/mole) 51+5.2x10 T- 5.7x10 T 6.8+1x10 T-0.11×10 T ZnO(s) CO (g) C (s) Zn (s) - 83.2 10.24 - 26.42 47.14 1.48 0.71 10 5.35 + 2.4×10T Zn (1) e Zn (o) 775

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 91QRT: Actually, the carbon in CO2(g) is thermodynamically unstable with respect to the carbon in calcium...
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Q: Pure ZnO is reduced by the stoichiometric amount of carbon as in the following
Reaction:
ZnO (s) + C (graphite) Zn (s) + CO (g)
=
Heat of fusion of zinc at melting point (420°C) = 1.74 kcal/mole and heat of
evaporation of zinc at boiling point (907°C) = 27.3 kcal/mole. Calculate the change in
free energy for the reaction at 907 °C.
Given that:
Material
AH°298 (kcal/mole)
S° 298
C, (cal/deg/mole)
(cal/deg/mole)
51+5.2x10 T- 5.7x10 T
6.8+1×10 T- 0.11×10° T
ZnO(s)
CO (g)
C (s)
Zn (s)
Zn (1) & Zn (g)
-83.2
10.24
- 26.42
47.14
1.48
0.71
10
5.35 + 2.4×10T
7.75
Transcribed Image Text:Q: Pure ZnO is reduced by the stoichiometric amount of carbon as in the following Reaction: ZnO (s) + C (graphite) Zn (s) + CO (g) = Heat of fusion of zinc at melting point (420°C) = 1.74 kcal/mole and heat of evaporation of zinc at boiling point (907°C) = 27.3 kcal/mole. Calculate the change in free energy for the reaction at 907 °C. Given that: Material AH°298 (kcal/mole) S° 298 C, (cal/deg/mole) (cal/deg/mole) 51+5.2x10 T- 5.7x10 T 6.8+1×10 T- 0.11×10° T ZnO(s) CO (g) C (s) Zn (s) Zn (1) & Zn (g) -83.2 10.24 - 26.42 47.14 1.48 0.71 10 5.35 + 2.4×10T 7.75
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