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- 1. A tensile test was conducted on a metal "505" specimen and the following stress-strain curves were generated, both curves generated from the same set of data. Use the graphs to fill in the mechanical properties of the material tested in the box below. Don't forget units! Stress vs Strain Stress, psi Stress, psi 80000 70000 60000 50000 40000 30000 20000 10000 0 0.00 80000 70000 60000 50000 40000 30000 20000 10000 0.02 0 0.000 0.002 0.04 0.004 0.06 0.006 0.08 0.10 Strain Stress vs Strain 0.008 0.12 Elastic Modulus, E: 0.2% Offset Yield Strength, oo: Tensile Strength, ou: Breaking Strength, of: % Elongation: 0.14 0.010 0.012 0.014 Strain 0.16 0.18 0.016 0.018 0.20 0.020The stress-strain data from a tensile test on a cast-iron specimen are € (10-3) 0 0.20 0.44 0.80 1.0 1.5 2.0 26 32 40 46 49 54 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 2.8 3.4 4.0 5.0 a (kpsi) 0 5 10 16 19 Determine the tangent modulus, E, at a value of a=0 psi. 106 psl. The tangent modulus, Eis Xa . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
- Consider the graph below for 3 test samples A, B and C of the same metal composition which have been cold-worked, but to different extents. If you had to sort the samples by the degree of cold-working they have undergone, how would you rank them? Stress (MPa) 600 500 4006 300 200 100 0 A B 0.05 1 0.1 0.15 Strain Select the correct answer: a. AStress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…Question A cylindrical specimen of metal having a diameter of 12.88 mm and a gauge length of 63.50 mm is tested using a tensile testing machine. The elongation measurement are recorded in Table 3. nPlot the stress-strain curve on the graph paper provided based on data in Table 3 Based on the stress-strain curved plotted in (i): Compute the modulus of elasticity Determine the yield strength at a strain offset of 0.002. Determine the tensile strength Determine the ductility in percent elongation and percent area reduction Table 3: Load-elongation readings for a metal specimen Jadual 3: Bacaan beban pemanjangan untuk statu spesimen logam) Load (N) Elongation (mm) 1380 0.03 2780 0.06 5630 0.12 7430 0.2 8140 0.25 9870 0.64 12850 1.91 14100 3.18 14340 4.45 13830 5.72 12500 6.99 FractureFrom the shear stress - shear strain diagram shown below, all the following are true except: Shear Stress (MPa) 500 450 400 350 300 250 200 150 100 50 0. 0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 Shear Strain (rad) Shear Stress-Strain Curve for Brass Select one: O a. Shear stress and Shear strain are 430 MPa and 1.72 rad at fracture. O b. Shear stress and Shear strain are 250 MPa and 0.05 rad at Yielding. Oc. The elastic zone ends at a shear stress of 400 MPa and shear strain of 1 rad Od. The ultimate Shear stress and Shear strain are 430 MPa and 1.72 rad.Table B2: Stress-strain data for uniaxial compression test on Sample Normal stress Uniaxial strain (%) Lateral strain (%) (MPa) 0.0 0.0000 0.0000 5.0 0.0319 -0.0150 10.0 0.0720 -0.0275 15.0 0.1025 -0.0425 20.0 0.1450 -0.0600 25.0 0.1755 -0.0725 30.0 0.2150 -0.0875 35.0 0.2455 -0.1025 41.0 0.2815 -0.1125 46.0 0.3125 -0.1209 52.0 0.3515 -0.1285 58.0 0.4000 -0.1325 (f) Based on the plotted curve, calculate the average/tangent Young's modulus and Poisson's ratio for this sample, at 50 % UCS?(d) Following experimental data (TableQ1b) has obtained from the torsion test for the specimen dimension given in Table Q1a. Determine the material of a circular bar. (Take the material Poisson's Ratio as 0.32) Table Q1a Specimen Dimensions Dimensions Material Diameter (mm) 6 Length (mm) 77.15 TableQ1b Experimental Results from Torsion test Angular Deflection Degree Radian Torque/Nm 0.5 0.008727 0.06 1 0.017453 0.47 1.5 0.02618 0.76 2 0.034907 1.01 2.5 0.043633 1.32 3 0.05236 1.65 3.5 0.061087 1.99 4 0.069813 2.32 4.5 0.07854 2.66 5 0.087267 3.00 5.5 0.095993 3.33 6 0.10472 3.64 10 0.174533 5.92 20 0.349066 7.74 30 0.523599 8.07 40 0.698132 8.17 50 0.872665 7.93 60 1.047198 8.10 70 1.221731 8.2 80 1.396264 8.4 90 1.570797 8.24 100 1.74533 8.7 110 1.919863 8.7 120 2.094396 8.7 180 3.141594 9.02 240 4.188792 9.11 300 5.23599 9.48 360 6.283188 9.51 420 7.330386 9.71A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lb - in per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in.in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lblb - in.in. per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.Figure 1 shows the tensile testing results for different materials. All specimens have an initial diameter of 12 mm and an initial gauge length of 50 mm. 300 250 Low carbon steel Network polymer 200 Crystalline polymer 150 Amorphous polymer 100 50 5 10 15 20 25 30 Strain (%) Figure 1: Stress-strain curve b. Determine the following parameters for each material: • the tensile strength the 0.2% offset yield strength the modulus of elasticity • the ductility Stress (MPa) LOSEE MORE QUESTIONS