Example: The half-wave rectifier in the figure has a 120-V rms source at 60 HzR = 500 02, and C= 100 µF. Determine (a) an expression for output voltage, (b) the peak-to-peak voltage variation on the output, (c) an expression for capacitor current, (d) the peak diode current, and (e) the value of C such that AVo is 1 percent of Vm
Example: The half-wave rectifier in the figure has a 120-V rms source at 60 HzR = 500 02, and C= 100 µF. Determine (a) an expression for output voltage, (b) the peak-to-peak voltage variation on the output, (c) an expression for capacitor current, (d) the peak diode current, and (e) the value of C such that AVo is 1 percent of Vm
Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
Problem 12SQ: How is a solid-state diode tested? Explain.
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![Example:
The half-wave rectifier in the figure has a 120-V rms source at 60 Hz R
= 500 02, and C= 100 µF. Determine
(a) an expression for output voltage,
(b) the peak-to-peak voltage variation on the output,
(c) an expression for capacitor current,
(d) the peak diode current, and
(e) the value of C such that AVo is 1 percent of Vm
Vs=Vm sin(cot)
+
ip](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3361ca50-fe39-4902-8c9b-25c25195dd96%2F74c24a51-244b-45ee-87ee-5930a6bfd9b0%2Fj8foyb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example:
The half-wave rectifier in the figure has a 120-V rms source at 60 Hz R
= 500 02, and C= 100 µF. Determine
(a) an expression for output voltage,
(b) the peak-to-peak voltage variation on the output,
(c) an expression for capacitor current,
(d) the peak diode current, and
(e) the value of C such that AVo is 1 percent of Vm
Vs=Vm sin(cot)
+
ip
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