For the reaction given below, the equilibrium constant (in terms of partial pressures) at 100°C is 11. N204(8) → 2N02(8) At equilibrium, the partial pressure of NO2 is 1.9 atm. What is the partial pressure of N2O4? a) 0.18 atm b) 0.33 atm c) 5.5 atm d) 4.0 atm

Chemistry: Principles and Reactions
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Chapter12: Gaseous Chemical Equilibrium
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For the reaction given below, the equilibrium constant (in terms of partial
pressures) at 100°C is 11.
N2O4(g) → 2NO2(g)
At equilibrium, the partial pressure of NO2 is 1.9 atm. What is the partial
pressure of N2O4?
a) 0.18 atm
b) 0.33 atm
O c) 5.5 atm
d) 4.0 atm
Transcribed Image Text:For the reaction given below, the equilibrium constant (in terms of partial pressures) at 100°C is 11. N2O4(g) → 2NO2(g) At equilibrium, the partial pressure of NO2 is 1.9 atm. What is the partial pressure of N2O4? a) 0.18 atm b) 0.33 atm O c) 5.5 atm d) 4.0 atm
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Equilibrium constant is equal to ratio of equilibrium partial pressure of product and equilibrium partial pressure of reactant.

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