Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0 A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes (x')^2/4 - (y')^2 = 1 Find the vertices of the conic in the xy-plane
Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0 A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes (x')^2/4 - (y')^2 = 1 Find the vertices of the conic in the xy-plane
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 25RE
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Given 7x^2 - 6sqrt(3)xy - 13y^2 - 16 = 0
A new equation after rotation using x = x'cos(theta) - y'sin(theta) and y = x'sin(theta) + y'cos(theta) becomes
(x')^2/4 - (y')^2 = 1
Find the vertices of the conic in the xy-plane
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