How many moles of your excess reactant are left after 54g of lithium iodide reacts with 5.0g of oxygen according to the equation below? 4 LiI   +   O2   -->   2 I2   +   2 Li2O

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Chapter4: Stoichiometry
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Problem 4.10PAE: 4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of...
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How many moles of your excess reactant are left after 54g of lithium iodide reacts with 5.0g of oxygen according to the equation below?

4 LiI   +   O2   -->   2 I2   +   2 Li2O

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