If one of the planets in our solar system averages 0.3871016 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)? the square root of (0.3871016)3 = 0.240845 Earth years the cubic root of (0.3871016)2 = 0.531149 Earth years the square root of (0.3871016)1/2 = 0.788781 Earth years the cubic root of (0.3871016)1/2 = 0.853698 Earth years the cubic root of (0.3871016)1/3 = 0.899918 Earth years
If one of the planets in our solar system averages 0.3871016 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)? the square root of (0.3871016)3 = 0.240845 Earth years the cubic root of (0.3871016)2 = 0.531149 Earth years the square root of (0.3871016)1/2 = 0.788781 Earth years the cubic root of (0.3871016)1/2 = 0.853698 Earth years the cubic root of (0.3871016)1/3 = 0.899918 Earth years
Principles Of Radiographic Imaging: An Art And A Science
6th Edition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Chapter40: Nuclear Medicine And Molecular Imaging
Section: Chapter Questions
Problem 1RQ
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Question
If one of the planets in our solar system averages 0.3871016 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)?
- the square root of (0.3871016)3 = 0.240845 Earth years
- the cubic root of (0.3871016)2 = 0.531149 Earth years
- the square root of (0.3871016)1/2 = 0.788781 Earth years
- the cubic root of (0.3871016)1/2 = 0.853698 Earth years
- the cubic root of (0.3871016)1/3 = 0.899918 Earth years
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