In a major metabolic pathway involving the monosaccharide glucose, one of the reactions involve the conversion of glucose to glucose-6-phosphate summarizedbelow together with accompanying free energy change:glucose + phosphate =glucose-6-phosphate + H,0 AG = 13.8 kJ · mol-1 (Reaction 1)In cells, the production of G6P (Reaction 1 above) is coupled to a reaction that involves the hydrolysis of ATP to ADP (shown below, Reaction 2) which makes theoverall reaction much more favorable to the production of glucose-6-phosphate.ATP + H,O = ADP + phosphate(Reaction 2)Why do you think coupling the production of glucose-6-phosphate to the hydrolysis of ATP makes the overall reaction spontaneous? What can you say aboutthe free energy change accompanying the hydrolysis of ATP (Reaction 2)?

The given reaction represents the first reaction of the glycolysis pathway. In this reaction, the…

Answered: In a major metabolic pathway involving…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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What terms would best describe the above coupled reaction? (If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for maltose synthesis from glucose + glucose is +3.7 kcal/mole, calculate the standard free energy change for the combined reaction of ATP + glucose + glucose g ADP + maltose + inorganic phosphate.) it is non-spontaneous and endothermic (because the overall DGo is negative) it is spontaneous and exothermic (because the overall DGo is negative) it is non-spontaneous and endothermic (because the overall DGo is positive) it is spontaneous and exothermic (because the overall DGo is positive) it is non-spontaneous and exothermic (because the overall DGo is negative)
The standard free energy change for the reaction catalyzed by phosphoglucomutase is -7.1 kJ/mol. Calculate the equilibrium constant for the reaction. Calculate AG at 37°C when the concentration of glucose-1-phosphate is 1-mM and the concentration of glucose-6-phosphate is 25-mM. Is the reaction spontaneous under these conditions? HOCH, -20;POCH, H H H H H H ОН Н НО ОН Н H НО ОН H ОН H. ОН Glucose-l-phosphate Glucose-6-phosphate
The enzyme aldolase catalyzes the reaction shown in the glycolytic pathway: Fructose 1,6-bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphate The AG" for the reaction is +23.8 kJ mol¯¹ (+5.7 kcal mol−¹), whereas the AG in the cell is −1.3 kJ mol¯¹ (−0.3 kcal mol¯¹). Calculate the ratio of products to reactants under standard (equilibrium) conditions at 37°C. [products] [reactants] 7 x10-5 [products] [reactants] Incorrect Aldolase ===== Calculate the ratio of products to reactants under intracellular conditions at 37°C. 4 ×10-5 Incorrect Complete the statement using your results. under standard conditions under intracellular conditions A reaction that is endergonic under standard conditions can be converted into an exergonic reaction by maintaining the ratio of products to reactants below the equilibrium value.
Glucose 1-phosphate is converted into fructose 6-phosphate in two successive reactions. Reaction 1: Glucose 1-phosphate → glucose 6-phosphate AG'° = -7.3 kJ/mol Reaction 2: Glucose 6-phosphate → fructose 6-phosphate AGʻ° = +1.7 kJ/mol Using the values given, calculate the standard free-energy change, AGʻ°, ,for the sum of the two reactions: sum > Sum: Glucose 1-phosphate → fructose 6-phosphate AG'°, kJ/mol sum Calculate the equilibrium constant, K', eq > for the sum of the two reactions. K'e eq II
Inside cells, the AG value for the hydrolysis of ATP to ADP + Pi is approximately -50 kJ/mol (-12 kcal/mol). Calculate the approximate ratio of [ATP] to [ADP][Pi ] in cells at 37°C. AG = AG + RT InKe R= 8.315 x 10³ kJ mol deg T= 298 K Table 15.1 Standard free energies of hydrolysis of some phosphorylated compounds Compound kJ mol- kcal mol- Phosphoenolpyruvate 1,3-Bisphosphoglycerate Creatine phosphate ATP (to ADP) -61.9 -14.8 -49.4 -11.8 -43.1 -10.3 -30.5 - 7.3 - 5.0 Glucose 1-phosphate Pyrophosphate Glucose 6-phosphate -20.9 -19.3 -4.6 -13.8 3.3 Glycerol 3-phosphate - 9.2 2.2 biochemistry
Consider the following phosphoryl group transfer reaction which is the first step in glucose catabolism by glycolysis: Glucose + ATP + Glucose 6-phosphate + ADP The AG for the reaction is -16.7 kJ/mol. (R= 8.314 J/(K. mol) (a) Calculate Keq for the reaction at 25°C (b) What is the ratio of [Glucose 6-phosphate] to [Glucose] if the ratio of [ADP] to [ATP] is 10?
The turnover number of the enzyme fumarase that catalyzes the reaction, Fumarate + H20 ===→ L-malate, is 2.5 x 103 S - l and Km = 4.0 X 10- 6 mol/L. Calculate the rate of conversion of fumarate to L-malate if the fumarase concentration is 1.0 x 1 0 - 6 mol/L and the fumarate concentration is 2.04 x 10- 4 mol/L.
G6P(ag) F6P(aq) AG°=+1.7kJ/mol at 25 °C Consider the reaction: Estimate the fraction of F6P (Fructose 6 Phosphate) in equilibrium with G6P (Glucose 6 Phosphate) at 25 °C, where the fraction is defined as [F6P]/([F6P]+[G6P]). Show ALL your work.
Consider the following list of phosphorylated compounds with their free energy changes of phosphate hydrolysis: Glucose-1-phosphate (-5.0 kcal/mol), PEP (-14.8 kcal/mole), 1,3-bisphosphoglycerate (-11.8 kcal/mole) and Glucose-6-Phosphate (-3.3 kcal/mol). Given that the free energy change of ATP hydrolysis is -7.3 kcal/mole, which of these molecules be directly synthesized by the transfer of a phospho- group from ATP? 1,3-bisphosphoglycerate Glucose-6-phosphate All of those phosphorylated compounds. PEP Glucose-1-phosphate
When grown anaerobically on glucose, yeast (S. cerevisiae) converts pyruvate to acetaldehyde, then reduces acetaldehyde to Pethanol using electrons from NADH. Write the chemical equation for the reaction that reduces acetaldehyde (CH3CHO) to ethanol (CH3CH2OH). The table provides the standard reduction potential, E', of the relevant half-reactions. Half-reaction Acetaldehyde + 2 H+ + 2e¯ → ethanol NAD+ + 2H+ + 2e¯ → NADH + H+ E'° (V) -.197 -.320 Calculate the equilibrium constant, K'eq, at 25.0 °C for the reaction that reduces acetaldehyde to ethanol. K'e ×10 = eq
The formation of maltose, a disaccharide, from two glucose molecules, is not energetically favorable. However, if this reaction is coupled with the hydrolysis of ATP, the reaction occurs more favorably. Maltose + H2O = 2 Glucose , ΔG'o = -15.5 KJ/mol or -3.7 kcal/mol a. Determine if the coupled reaction will occur spontaneously at standard state through calculating the Gibbs Free Energy of Reaction. b. Calculate the equilibrium constant for each individual reaction, and for the coupled reaction (using free energy of reaction). Show that the equilibrium constant for the coupled reaction equals the equilibrium constants for the individual reactions multiplied together. c. If the reaction medium contains the following chemical species at their given concentrations (298 K and 1.0 atm, pH = 7.0), will the reaction proceed in the forward or the reverse direction? [Maltose] = [Glucose] = 10.0 mM; [ATP] = 5.0 mM; [ADP] = [Pi] = 20 mM
Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 23.7, and the temperature is 37.0 °C? AG" for the reaction is -16.7 kJ/mol. The constant R = 8.3145 J/(mol-K) AG= Number kJ/mol

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