In a site balancing project, the total haul distance starts from Sta. 2+720 and ends in Sta. 4+450. The freehaul distance starts 430 m. away from the starting station of the total haul distance and ends before the total haul distance which is also at a distance of 430 m. a. Get the total haul distance b. Locate the starting and end stations of the free haul distance c. Get the overhaul distance.
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- If the free haul area is between 4+30 and 14+30, what is the average haul distance (ft) for the net volume of material taken from the section between station 2+60 and 3+00? Response Feedback: The average distance between 2+60 and 3+00 is 20 ft. Add that to the distance from 3+00 to the free haul area, which begins at 4+30.The mass ordinates at the initial point ( sta 0+000) of a mass diagram is 50 cu m ,and at the last station (0+280) is - 200 cu m .If the length of economical haul is plotted horizontally to intersect the ( summit ) the mass diagram at a point having a mass ordinate of 120 cu m .The length of economical haul is 250 m long, compute the volume of borrowFor the following mass haul diagram loop shown below, calculate the cost of earthwork, including excavation and hauling given that the cost of excavation is $2.0/m³ and the cost of overhaul is $0.150/m³.station. (Hint: Numbers shown on the loop are accumulative volumes (m³)) 1760 2150 2280 FHD = 200 m LEHD = 350 m
- Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 g t--------- 6.0 8.0 O 1000 1,100 - 7.1 750 5.0 TO -1000 3-2000 -3000 -3,000 ´ -4000 -5000 5 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total excavation cost to the nearest dollar? $30,000 O $28,000 $25,375 $20,250 O None of the above Net Cumulative YardageNet Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 None of these. 11.7 6.0 O 8.0 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: O 12.0 -3,000 1,500 5 2,100 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
- The following net accumulations were calculated. The free haul area begins at station 4+30 and continues to 14+30. If the overhaul is charged at $10/yd³ station, what is the total overhaul cost ($)? Round to the nearest cent. from station to station net accumulation, yd³ 2+60 3+00 3.85 3+00 4+00 5.85 4+00 4+30 8.35 Response Feedback: 10x8.35x0.9281Q1) For the following portion of mass haul diagram (each station is 50 m) answer the following questions: Station 4+00 7+00 6+00 5+00 3+00 2+00 1+00 0+00 -100 200 300 400 500 600 -700 -800 A) If the free haul distance =150 m, find the total cost within the free haul distance if the cost of excavation and transporting up to 150 m = 0.5 JD/ m? B) Find the limit of economical haul distance if the cost transporting is 0.1 JD/ m' for each 30 m beyond the first 150 m? C) Find the volume of waste and borrow materials? D) On the figure above specify the following: · Free haul distance and volume • Limit of economical haul distance and the overhaul volume • The waste and borrow material portion comulative volume m'ASAP PLS I RLLY NEED THIS IN 30 MINUTES
- need within 1hr, pls thank youQ- A tractor has a permissible loaded speed of 200 m/minute, which can increase by 25% when the load is removed/deposited. Generally, it is operated at 80% of the permissible speed (loaded unloaded). It works at a location where haul distance is 120 m. Rest allowance per round-trip is taken as 50 seconds on an average. Fixed time per trip, for loading and unloading and turnaround, etc., is 30 seconds. What is its effective cycle time?Determine the length of overhaul if the cost of hauling is P192000.0