く Membership of a point in an interval [ ] # @title Membership of a point in an interval def interval_contains(self, x): ### YOUR SOLUTION HERE Interval. contains _ = interval_contains [ ] # Tests 10 points. assert 3 in Interval(3, 5) assert not (1 in Interval(3, 5))
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- function loginValidate () { var id = document.getElementById ('myid').value; var pass = document.getElementById('mypassword').value; if ((id == null : id alert ("ID and Pasword both must be filled out") : "") && (pass == null , pass == ")){ == return false: else if (id == null || id == "") { alert ("ID must be filled out "); return false; else if (pass == null || pass == "") { alert ("Password must be filled out "); return false;PLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…class Solution(object): def longestCommonPrefix(self, strs): result ="" for i in strs[0]: for j in strs[1]: for k in strs[2]: if i == j and i == k: result+=i if len(result) >0: return result else: return result IndexError: list index out of range for j in strs[1]: Line 5 in longestCommonPrefix (Solution.py) ret = Solution().longestCommonPrefix(param_1) Line 31 in _driver (Solution.py) _driver() Line 41 in <module> (Solution.py) can someone explain why this is wrong?
- C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".Computer Engineering HandsOn Lab: The Government of United States of America has decided to issue new currency notes with special protection features to so as to commemorate a great mathematician. They have decided to issue notes summing up to N and all the sums from 1 to N should only made by selecting some of the notes in only one unique way. With n = 5 the sets {1,1,1,1,1}, {1,2,2}, {1,1,3} are valid. Your task is to design a C++ code that output the solution in one line. Sample Input - 100 Sample Output - 3Python Language Q2: Ginormous Campus The campus is pretty big. There are n buildings scattered around it, numbered from 0 to n-1. These buildings are so far away from each other that the only way to get from one to another is to take a campus bus. There are m campus bus routes. The i-th one (0 <= i < m) takes you from building u_i to building v_i (but not the other way around). These buses run very frequently. Professor Zingaro is deciding where to hold his CS lectures. He believes a building x is accessible from a building y if you can get from y to x taking at most two buses. For his students’ convenience, he wants to hold his lectures in the most accessible building. Help him out by telling him how many buildings the most accessible building is accessible from. In addition, list all buildings that are the most accessible. Input The first line of the input contains two space-separated integers n and m, denoting the number of buildings and bus routes, respectively. m lines…
- Computer Science A tool is attached to link 3 of the manipulator. This tool is described by TTW, the tool frame relative to the wrist frame. Also, a user has described his work area, the station frame relative to the base of the robot, as TSB. Write the subroutine Procedure SOLVE(VAR trels: frame; VAR current, near, far: vec3; VAR sol: boolean); where “trels” is the {T} frame specified relative to the {S} frame. Other parameters are exactly as in the INVKIN subroutine. The definitions of {T} and {S} should be globally defined variables or constants. SOLVE should use calls to TMULT, TINVERT, and INVKINDeliverable #2: How many operations in nested for loops? Implement the following psuedocode as the function two_dimensional_loop (n) in the cell below: count = 0 for i = 0 to n-1 : for j = i to n-1 : count = count + 1 return count ► def two_dimensional_loop(n) : # complete to satisfy the instructions and implement the pseudocode || return 0 expectEqual (two_dimensional_loop (520),135460) expectEqual (two_dimensional_loop (1234), int(1234* (1234+1)/2)) 个 ↓Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews O
- A/ find code optimization method to this code and then find type to this code 1- For(i=1;istruct insert_into_hash_table { // Function takes a constant Book as a parameter, inserts that book indexed by // the book's ISBN into a hash table, and returns nothing. void operator()(const Book& book) { ///// /// TO-DO (8) ||||. // Write the lines of code to insert the key (book's ISBN) and value // ("book") pair into "my_hash_table". /// END-TO-DO (8) // } std::unordered_map& my_hash_table; };A class object can encapsulate more than one [answer].SEE MORE QUESTIONS