-mg=Dapparent weight of object m= opparent mass at object = 100g 9= 993.18 drn Vニtrh %3D 9= 978 dyu S- density of abject = 5.51 9 Cm 3 P= density of water= 1-1 VE valume of object=18.14 cm w= (P-P)JU Find differen tiad emar of g sh=or= 0.0s cm %3D sm'=0.5g
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