Oxygen gas can be prepared by heating potassium chlorate according to the following equation 2KCIO3(s)2KCI() +302(g) The product gas, O,, is collected over water at a temperature of 25 °C and a pressure of 741 mm Hg. If the wet O, gas formed occupies a volume of 7.54 L, the number of moles of KCIO3 reacted was mol. The vapor pressure of water is 23.8 mm Hg at 25 C
Oxygen gas can be prepared by heating potassium chlorate according to the following equation 2KCIO3(s)2KCI() +302(g) The product gas, O,, is collected over water at a temperature of 25 °C and a pressure of 741 mm Hg. If the wet O, gas formed occupies a volume of 7.54 L, the number of moles of KCIO3 reacted was mol. The vapor pressure of water is 23.8 mm Hg at 25 C
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Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.117QP: Liquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain...
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![Oxygen gas can be prepared by heating potassium chlorate according to the following equation
2KCIO3(s)2KCI() +302(g)
The product gas, O,, is collected over water at a temperature of 25 °C and a pressure of 741 mm Hg. If the wet O, gas formed occupies a volume of 7.54 L, the
number of moles of KCIO3 reacted was
mol. The vapor pressure of water is 23.8 mm Hg at 25 C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48deb947-3d41-43de-ac43-bef03e01cc59%2F88159f17-2471-42d6-9b47-d28fe07c3a96%2Fi0cleb.png&w=3840&q=75)
Transcribed Image Text:Oxygen gas can be prepared by heating potassium chlorate according to the following equation
2KCIO3(s)2KCI() +302(g)
The product gas, O,, is collected over water at a temperature of 25 °C and a pressure of 741 mm Hg. If the wet O, gas formed occupies a volume of 7.54 L, the
number of moles of KCIO3 reacted was
mol. The vapor pressure of water is 23.8 mm Hg at 25 C
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