Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a21² + a31³, calculate the coefficient a3. - cos(57) sin(31)
Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a21² + a31³, calculate the coefficient a3. - cos(57) sin(31)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 3E
Question
![Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) cos(57) sin(37)
near0 such that
g(t) = P3(t) + R3(0, 1)
in some interval where R3(0, 1) is the remainder term. Writing P3(t) as
P3(1)=ao+at+a27² + a31³,
calculate the coefficient a3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff76dba93-23d2-47f1-b92c-ad2c0bf14e16%2F7e0224de-6eb6-4243-9f18-a98f02298fd6%2Fmug1xuf_processed.png&w=3840&q=75)
Transcribed Image Text:Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) cos(57) sin(37)
near0 such that
g(t) = P3(t) + R3(0, 1)
in some interval where R3(0, 1) is the remainder term. Writing P3(t) as
P3(1)=ao+at+a27² + a31³,
calculate the coefficient a3.
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