Provide a structure for the given compound. molecular mass 101; IR: 3397, 3200, 1655, 1622 cm-¹; 13C NMR: 6 27.5, 8 38.0 (weak), 8 180.5 (weak). Draw the compound. Select / |||||| Draw H N Templates O More
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- 2. Compound A, C;H100 , is one of the basic building blocks of nature. All steroids and many other naturally occuring compounds are built from compound A. Spectroscopic analysis of A yields the following information: IR: 3400 cm-'; 1640 cım- IH NMR: 1.63 & (3 H, singlet); 1.70 ô (3 H, singlet); 3.83 6 (1 H, broad singlet); 4.15 8 (2 H, doublet, j = 7 Hz); 5.70 ô (1 H, triplet, ) = 7 Hz) (a) How many double bonds and/or rings does A have? (b) From the IR spectrum, what is the identity of the oxygen-containing functional group? (c) What kinds of protons are responsible for the NMR absorptions listed ? (d) Propose a structure for A.4G 4G ill iill 1:54 PM 43 ... H2NCH;CH,CHNH2 CH3 3. Draw structures corresponding to the following IUPAC names: (a) Triethylamine (b) N-Methylaniline (c) Tetraethylammonium bromide (e) N-Ethyl-N-methylcyclopentylamin (d) p-BromoanilinePlease provide the IUPAC name (only) for the compound that best represents the spectroscopic data here: • Molecular formula: C4H100 Important IR data (cm 1): 3280 (broad); 2910-2950 (many); 1053 • All 'H NMR data shown as x.xx ppm (splitting), integration. 1.23 ppm (t), 3 1.23 ppm (d), 3 "-OH" 1.46 ppm (m), 2 4.03 ppm (m), 1 5. PPM
- of 10 Provide a structure for the compound with the formula C, H,NO using the given information. 13 IR: 3360, 3280 cm- (doublet); 1611 cm-; no carbonyl absorption; 'H NMR spectrum: chemical shift, Hz 1200 2400 2100 1800 1500 900 600 300 3H J = 6.9 Hz J = 6.9 Hz J = 8.7 Hz |= 8.7 Hz 4H 2H 2H 2H 7 4 chemical shift, ppm (8) 3 1 0. Draw the structure C, HNO. 13 Select Draw Rings More Erase // C H N 5. 6 8Provide a structure for the compound with the formula C,H, NO using the given information. IR: 3360, 3280 cm (doublet); 1611 cm¯"; no carbonyl absorption; 'H NMR spectrum: chemical shift, Hz 1200 2400 2100 1800 1500 900 600 300 3H J = 6.9 Hz J= 6.9 Hz J = 8.7 Hz J = 8.7 Hz 4H 2H 2H 2H 8. 6. 4 chemical shift, ppm (8) 3 APR étv Aa MacBook AirDetermine product (A) of the reaction (1) NK + DMF CH2 – Br (A) (81%) (2) HO¯/H2O (Benzyl bromide) (a) Ph – NH2 (c) Ph – CH2 – NH – CO,H (b) Ph – CH2 – NH2 (d) Ph – CH, - NH – CHO
- 5. (Chapter 15 - Q41b) Propose a structure for the compound that fits the following description. C30H14 7.0 8, (4H, broad singlet) 2.85 (1H, septet J = 8 Hz) 1.20 5 (6H, doublet J=8 Hz) 2.28 6 (3H, singlet) IR: 825 cm 1 5(a) Degree of the unsaturation of this compound is= 5(b) Two peaks at 2.85 o and 1.20 õ indicate that the compound has. group = 4(c) A peak at 2.28 õ indicates that the compound has. group= 4(d) IR absorption indicates the compound is .-disubstituted = 4(e) The name of the compound is =Draw out the structure: The Key signals for IR are = 3090, 2800-3000,1700,1455,1560,1598,1110,1290 cm^-1. MS is = M+ 150,m/z121,105,77. 1H NMR is=7.5 –7.9 m,4.1 q,1.2 t.; 13C NMR: 14.4,60.8,128.4,129.7,131,133,167ppmReaction of acetic acid, CH3CO2H, with isotopically labeled CH318OH and catalytic sulfuric acid gives: 180 A) CH;COCH; + H2O CH;C "OCH; + H,0 180 II C) CH;COCH3 + H¿®O D) equal amounts of A and B
- 4G 4G illl 1:54 PM 43 ... 2. Name the following compounds: (c) CH3 CH3CHNH2 (a) (b) CH3CH2NHCH,CH3 N-CH3 (d) CH2CH3 (e) H CH3 H2NCH2CH2CHNH24G 4G 1:54 PM 43 ... H2NCH,CH,CHNH2 CH3 3. Draw structures corresponding to the following IUPAC names: (a) Triethylamine (b) N-Methylaniline (c) Tetraethylammonium bromide (e) N-Ethyl-N-methylcyclopentylamin (d) p-BromoanilineComplete the following answer using the data provided here: • Molecular formula: C5H10O2 • Important IR data (cm-1): 3150-3010 (many); 1740; 1248; 1050 • All 'H NMR data (ppm, splitting, integration): 3.66 ppm (s), 3; 2.20 ppm (t), 2; 1.80 ppm (m), 2; 0.98 ppm (t), 3 Which of the following best fit this spectroscopic data? OH H. A C D E