Question: The relationship between temperature and volume of a gas is linear andgiven by Charl's lawV (ml) = Constant x T (°C)T (°C) V (ml)-238.41525-138.751869.088479.425089.76169-3717a. -250 Cb. -290 Cc. -270 Cd. -273 C27374757677710.0983010.4349110.7715211.1081311.4447411.78135Calculate the temperature (°C) at which the volume of the gas become close to zero.Hints:1. The temperature of the gas at which the volume is close to zero is obtained byextrapolation of the best fit straight line to the V≈ 0.2.The extrapolation in Excel is carried out by: Right click on the straight line→From the dropdown menu select Format Trend line → Forecast → backward→Type 250 in the blank field.

The given data are, Extrapolating the y-axis will give the value for temperature when the volume…

Question: The relationship between temperature and volume of a gas is linear and given by Charl's law V (ml) = Constant × T (°C) T(°C) -23 -13 -3 7 17 27 37 47 57 67 77 V (ml) 8.41525 8.75186 9.08847 9.42508 9.76169 10.09830 10.43491 10.77152 11.10813 11.44474 11.78135 Calculate the temperature (°C) at which the volume of the gas become close to zero.

Question: The relationship between temperature and volume of a gas is linear and given by Charl's law V (ml) = Constant × T (°C) T(°C) -23 -13 -3 7 17 27 37 47 57 67 77 V (ml) 8.41525 8.75186 9.08847 9.42508 9.76169 10.09830 10.43491 10.77152 11.10813 11.44474 11.78135 Calculate the temperature (°C) at which the volume of the gas become close to zero.

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 7CR

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