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System 1 is a "Modulator" that multiplies an incoming signal z(t) by cos(6лt); so that its output is y(t) = z(t) cos(6nt). [This does NOT mean that the impulse response of System 1 is cos(6πt)!] System 2 is an ideal Low-Pass Filter with a cutoff frequency of 3 Hz. These two systems are connected in cascade (in series), with System 2 coming before System 1 as shown below: x(t) System 2 System 1 y(t) The input signal applied to System 2 has a Fourier Transform spectrum of X(f) = 0.5tri(f/4) = 0.5 - f/4, for -2

System 1 is a "Modulator" that multiplies an incoming signal z(t) by cos(6лt); so that its output is y(t) = z(t) cos(6nt). [This does NOT mean that the impulse response of System 1 is cos(6πt)!] System 2 is an ideal Low-Pass Filter with a cutoff frequency of 3 Hz. These two systems are connected in cascade (in series), with System 2 coming before System 1 as shown below: x(t) System 2 System 1 y(t) The input signal applied to System 2 has a Fourier Transform spectrum of X(f) = 0.5tri(f/4) = 0.5 - f/4, for -2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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System 1 is a "Modulator" that multiplies an incoming signal z(t) by cos(6лt); so that its output is y(t) = z(t) cos(6nt). [This does NOT mean that the impulse response of System 1 is cos(6πt)!] System 2 is an ideal Low-Pass Filter with a cutoff frequency of 3 Hz. These two systems are connected in cascade (in series), with System 2 coming before System 1 as shown below: x(t) System 2 System 1 y(t) The input signal applied to System 2 has a Fourier Transform spectrum of X(f) = 0.5tri(f/4) = 0.5 - f/4, for -2<f <2 Draw the magnitude of the input signal spectrum (X(f), the magnitude spectrum of the signal exiting the first system System 1 and entering the 2nd system System 2 (call this signal | Z(f))), and draw and describe the output signal spectrum |Y(f) using the expression below: E Enter only positive values: A= type your answer... D= type your answer... type your answer... ||Y (f)| = rect (A). (Ctri (1+D) + Ftri (: f-G H B-type your answer... ,E-type your answer... ,F- type your answer... (enter the smallest possible value), C= type your answer... ,G= type your answer... ,H=
Transcribed Image Text:System 1 is a "Modulator" that multiplies an incoming signal z(t) by cos(6лt); so that its output is y(t) = z(t) cos(6nt). [This does NOT mean that the impulse response of System 1 is cos(6πt)!] System 2 is an ideal Low-Pass Filter with a cutoff frequency of 3 Hz. These two systems are connected in cascade (in series), with System 2 coming before System 1 as shown below: x(t) System 2 System 1 y(t) The input signal applied to System 2 has a Fourier Transform spectrum of X(f) = 0.5tri(f/4) = 0.5 - f/4, for -2<f <2 Draw the magnitude of the input signal spectrum (X(f), the magnitude spectrum of the signal exiting the first system System 1 and entering the 2nd system System 2 (call this signal | Z(f))), and draw and describe the output signal spectrum |Y(f) using the expression below: E Enter only positive values: A= type your answer... D= type your answer... type your answer... ||Y (f)| = rect (A). (Ctri (1+D) + Ftri (: f-G H B-type your answer... ,E-type your answer... ,F- type your answer... (enter the smallest possible value), C= type your answer... ,G= type your answer... ,H=
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