The word's length in a finite language with its FA of ten states Ⓒ must be less than ten length of all words in this language is exactly ten may be greater than ten undetermined by the given information To test if an FA of 4 states over alphabets Σ accepts any string or not, Otest only strings of length 4 C test all strings with length less than 4 Otest one string of length greater than 4 check all possible strings of

The word's length in a finite language with its FA of ten states Ⓒ must be less than ten length of all words in this language is exactly ten may be greater than ten undetermined by the given information To test if an FA of 4 states over alphabets Σ accepts any string or not, Otest only strings of length 4 C test all strings with length less than 4 Otest one string of length greater than 4 check all possible strings of

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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z wne aprogaminCtlanguagutoreadthenansa of the souroeof studerta and thar gradea far farsatjecta andfinddhe avarage tar eachanudant dhat youshow anddanpivedenanesof the snuderna verscally andaganst each student's name and it is in a sequential manner from the first student according to the average between them down to the last student calculating the rate 2 Write a C++ program that contains a function to build the loose arithmetic and a second function Calculate the following equation 8! .10! y = t. x11! It calls a function inside another function 3. Assignment for the previous electronic lecture Write a program to read five integers and store them in a single array, then use a function that you build to create a new array of three columns and five rows. The function Func1 (input array, output array) is as follows Input 10 15 3 13 10 10 20 15 15 30 Output 3 7 14 13 13 26
4. LetΣ ={a, b}. LetL={aibai|i≥0}.Give a Turing machine (TM) that accepts the languageL.Assume (as in the examples done in our course videos) that, when theTM starts, the head is on a blank symbol,∆, and the input string isimmediately after that blank symbol on the tape. For example, if theinput string wereaaabaaa, then the inital tape configuration would be∆aaabaaa
Correct answer will be upvoted else Multiple Downvoted. Computer science. inquiry is depicted by a couple of integers li, ri (1≤li<ri≤n). For each question, he needs to decide if there exists a decent aftereffect in s that is equivalent to the substring s[li… ri]. A substring s[i… j] of a string s is the string shaped by characters sisi+1… sj. String an is supposed to be an aftereffect of string b if a can be gotten from b by erasing a few characters without changing the request for the excess characters. An aftereffect is supposed to be acceptable in case it isn't coterminous and has length ≥2. For instance, in the event that s is "1100110", the aftereffects s1s2s4 ("1100110") and s1s5s7 ("1100110") are acceptable, while s1s2s3 ("1100110") isn't acceptable. Would you be able to help Hr0d1y answer each question? Input The primary line of the input contains a solitary integer t (1≤t≤100) — the number of experiments. The portrayal of each experiment is as per the…
Let the domain of discourse be all animals. Translate "There is an animal that is slower than every dog" using this translation key: Dx x is a dog Bx x likes basketball moves Fxy x is faster than y Р Pepper q Quincy Rascal r Use A and E for the quantifier symbols, just like we do with the proof checker. Your answer should be the formula and nothing else.
13. Draw a deterministic FSM that recognizes strings of 1’s and 0’s specified by each of thefollowing criteria. Each FSM should reject any characters that are not 0 or 1. *(a) The stringof three characters, 101. (b) All strings of arbitrary length that end in 101. For example, theFSM should accept 1101 but reject 1011. (c) All strings of arbitrary length that begin with 101.For example, the FSM should accept 1010 but reject 0101.
Correct answer will be upvoted else downvoted. Computer science. You have c1 letters 'a', c2 letters 'b', ..., c26 letters 'z'. You need to construct a lovely line of length n from them (clearly, you can't utilize the I-th letter more than ci occasions). Every ci is more noteworthy than n3. A string is called delightful in case there are no palindromic coterminous substrings of odd length more prominent than 1 in it. For instance, the string "abacaba" isn't wonderful, it has a few palindromic substrings of odd length more noteworthy than 1 (for instance, "aca"). Another model: the string "abcaa" is wonderful. Work out the number of various strings you can assemble, and print the appropriate response modulo 998244353. Input The main line contains one integer n (3≤n≤400). The subsequent line contains 26 integers c1, c2, ..., c26 (n3<ci≤n). Output Print one integer — the number of strings you can construct, taken modulo 998244353.
In computational complexity theory, we study mostly decision problems (e.g., determine if aBoolean formula has a satisfying assignment), instead of the search problems that are typicallywhat practicing computer scientists really want to solve (e.g., determine if a Boolean formula hasa satisfying assignment, and then output the assignment). It is natural to wonder whether we arestudying the wrong thing. In this exercise, you will show that the difficulty of decision problems isin fact linked closely to that of search problems.Show that if P = NP, then every NP search problem can be solved in polynomial time. In otherwords, for each language A ∈ NP, with a polynomial-time verifier algorithm VA taking inputs x, w,where x ∈ A ⇐⇒ (∃w) VA(x, w) accepts, then there is a polynomial-time algorithm S that, oninput x, does the following. If x ̸∈ A, then S(x) outputs “no”. If x ∈ A, then S(x) outputs w suchthat VA(x, w) accepts.Hint: Build up the witness w bit by bit, by asking NP questions about…
Correct answer will be upvoted else downvoted. Computer science. string a matches an example b if for every I from 1 to k either bi is a special case character or bi=ai. You are approached to improve the examples so that the primary example the j-th string matches is p[mtj]. You are permitted to leave the request for the examples unaltered. Would you be able to perform such an improvement? Assuming you can, print any legitimate request. Input The primary line contains three integers n, m and k (1≤n,m≤105, 1≤k≤4) — the number of examples, the number of strings and the length of each example and string. Every one of the following n lines contains an example — k characters that are either lowercase Latin letters or highlights. All examples are pairwise unmistakable. Every one of the following m lines contains a string — k lowercase Latin letters, and an integer mt (1≤mt≤n) — the record of the main example the relating string should coordinate. Output Print "NO"…
What does the Pumping lemma for regular languages say? Select one: O Every "long enough" word in language L can be written in the form uv'w. O If a language L contains a "long enough" word z=uvw, then L contains infinitely many words of the form uv w. O Every word that can be written with a regular expression, can be also "pumped". O For an arbitrary word z=uvw in language L, there exist infinitely many words of the form uv'w, that are also in L.
The Infinite Monkey Theorem states that a monkey hitting keys completely at random on a typewriter for an infinite amount of time will, eventually, type any given text. Even the complete works of William Shakespeare. Some quotes are truly amazing. Consider the famous quote, "BREVITY IS THE SOUL OF WIT" That's 26 amazing characters. Suppose a monkey is seated in front of a KEYBOARD WITH 28 CHARACTERS (one for each of the 26 letters in the alphabet, plus the space bar, and a comma). Suppose the monkey types only 26 characters completely at random. If X is the number of different 26 character strings it could have typed, then the chances that it typed the quote is one divided by X. What is X?
C-F languages (or see the following figure). In particular..it points out that the language {am,a"b" | m,n = N} is a deterministic C-F language, but not LL(k) for any k Palindromes over {a, b} Non-deterministic C-F {am,a"b" | m.ne N}; Deterministic C-F -LL(K) {ab❘n EN}- Regular To show the language is not LL(k) for any k, note that a grammar for this language is SAB A→ B -> 10 or S-A|B A→ B (you only need to answer one case here, either one). The language contains A as an element. Now consider the case k = 1 and consider the input string ab. When the first symbol is scanned, we get an 'a'. This information alone is not enough for us to make a proper choice. So we don't even know what to do with the first step in | the parsing process. For k = 2, if we consider the input string aabb, we face the same problem. For any k > 2, the input string ab would cause exactly the same problem. So this grammar is not LL(k) for any k. On the other hand, by putting proper instructions into the blanks…
A string w of a's and b's is valid if it satisfies one of the following conditions: • w is the empty string • w = aub for some valid string u • w = uv for some valid strings u and v For example, the string w = aaabbabbaabbab is valid, because w : = uv, where u = aaabbabb and v= aabbab. Describe an efficient algorithm to determine whether a given string of a's and b's is valid. Analyze its time and space requirements. (Aim for solving the problem in linear time.) Show how the algorithm works on the above example.