Unit: BTU HL = Heat loss (BTU)= Hv x hours If loss for one day, H = 24 hrs If we are talking about a D days then H = 24 hrs x D (e.g. During February, H= 24 hrs x 28 days) In summary heat loss for D days is HL = (A/R) * AT* D days *24 hrs Home Heat Loss Calculation Table Use coldest month of Feb (28 days) average of 20 degree ºF outside. Assume inside temperature of the house is 70 °F
Unit: BTU HL = Heat loss (BTU)= Hv x hours If loss for one day, H = 24 hrs If we are talking about a D days then H = 24 hrs x D (e.g. During February, H= 24 hrs x 28 days) In summary heat loss for D days is HL = (A/R) * AT* D days *24 hrs Home Heat Loss Calculation Table Use coldest month of Feb (28 days) average of 20 degree ºF outside. Assume inside temperature of the house is 70 °F
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter1: Basic Modes Of Heat Transfer
Section: Chapter Questions
Problem 1.22P: 1.22 In order to prevent frostbite to skiers on chair lifts, the weather report at most ski areas...
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![Unit: BTU
Surface Type
Wall
Home Heat Loss Calculation Table
Use coldest month of Feb (28 days) average of 20 degree °F outside. Assume inside temperature of the house is 70 °F
Table 8-2
Ceiling
Window
If loss for one day, H = 24 hrs
If we are talking about a D days then H = 24 hrs x D (e.g. During February, H= 24 hrs x 28 days)
Door
HL=Heat loss (BTU)= Hv x hours
Area (ft²)
In summary heat loss for D days is
HL= (A/R) * AT* D days *24 hrs
Insulation R-value
(from Table 8-1)
ΔΤ (°F)
Daily (1 day)
Loss in BTUS
Grand total of all conduction heat losses in BTU Σ
28 day month
lost in BTU
Σ
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F175c6072-41a9-4c1b-88b7-e1a72d6f6f85%2F3726f640-3eb0-453b-8e01-689d71f3bf1c%2Fb3d592z_processed.png&w=3840&q=75)
Transcribed Image Text:Unit: BTU
Surface Type
Wall
Home Heat Loss Calculation Table
Use coldest month of Feb (28 days) average of 20 degree °F outside. Assume inside temperature of the house is 70 °F
Table 8-2
Ceiling
Window
If loss for one day, H = 24 hrs
If we are talking about a D days then H = 24 hrs x D (e.g. During February, H= 24 hrs x 28 days)
Door
HL=Heat loss (BTU)= Hv x hours
Area (ft²)
In summary heat loss for D days is
HL= (A/R) * AT* D days *24 hrs
Insulation R-value
(from Table 8-1)
ΔΤ (°F)
Daily (1 day)
Loss in BTUS
Grand total of all conduction heat losses in BTU Σ
28 day month
lost in BTU
Σ
2
![ET 842
Window insulation: U-factor and R-value:
U-factor measures how well a product prevents heat from escaping a home or building (thermal conductivity). U-factor
ratings generally fall between 0.15 and 1.20. (See more at: http://www.nfrc.org/windowratings/Energy-
ratings.html#sthash.EUkrrint.dpuf)
A lower U-factor means a better-insulating window.
The more common term R-value refers to the resistance of the window to heat conduction, and it is the inverse of the U-
factor (that is, R-value = 1/U-factor). Better windows have high R-values and low U-factors.
Determine all surface type of areas in Table 8-1 from the house in figure 1 and calculate R-values with the given U-factor.
Surface Type
Table 8-1
a) Walls
b) Ceiling (**Assume the ceiling area is the same as rectangular floor
area, A=L x W)
c) Total window x 8 ea
(argon-filled, double glazed for all windows)
d) Total door (insulated steel entry doors) x 2ea
Size of area
(width x height = ft²)
3300 ft^2
1800 ft^2
72 ft^2
28 ft^2
U-factor R-values
0.06
0.025
Prof. Seo
0.35
0.20
16.66
40
2.85
5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F175c6072-41a9-4c1b-88b7-e1a72d6f6f85%2F3726f640-3eb0-453b-8e01-689d71f3bf1c%2F1bxx3gi_processed.png&w=3840&q=75)
Transcribed Image Text:ET 842
Window insulation: U-factor and R-value:
U-factor measures how well a product prevents heat from escaping a home or building (thermal conductivity). U-factor
ratings generally fall between 0.15 and 1.20. (See more at: http://www.nfrc.org/windowratings/Energy-
ratings.html#sthash.EUkrrint.dpuf)
A lower U-factor means a better-insulating window.
The more common term R-value refers to the resistance of the window to heat conduction, and it is the inverse of the U-
factor (that is, R-value = 1/U-factor). Better windows have high R-values and low U-factors.
Determine all surface type of areas in Table 8-1 from the house in figure 1 and calculate R-values with the given U-factor.
Surface Type
Table 8-1
a) Walls
b) Ceiling (**Assume the ceiling area is the same as rectangular floor
area, A=L x W)
c) Total window x 8 ea
(argon-filled, double glazed for all windows)
d) Total door (insulated steel entry doors) x 2ea
Size of area
(width x height = ft²)
3300 ft^2
1800 ft^2
72 ft^2
28 ft^2
U-factor R-values
0.06
0.025
Prof. Seo
0.35
0.20
16.66
40
2.85
5
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Follow-up Questions
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Follow-up Question
1. If 1 gallon of oil = 1.4 therm, how many gallons have been wasted by heat loss in Feb? (1 therm = 100,000 BTU)
_____________________________________________________________________________________
2. If $1.30 per therm, how much did you waste from house heat loss in Feb?
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