scale model by Lochridge

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School

Georgia Highlands College *

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Course

1000

Subject

Astronomy

Date

Apr 3, 2024

Type

docx

Pages

12

Uploaded by abi22l on coursehero.com

ASTR 1000: The Size of our Solar System Name: _____Abi lochridge__ Be certain to review the scale models video (D2L --> Content Browser --> Chapter 1), and check out the example of a kitchen table scale model in the ASTR Project Options overview document (D2L --> Content Browser --> Additional Resources) before getting started. First, check out the links below to get a feel for the sizes of the planets in our Solar System: http://www.space.com/30610-scale-of-solar-system-amazing-video.html https://www.youtube.com/watch?v=NC4pLkUYpjA Now construct a scale model of our solar system that fits on your kitchen table and another that fits in your driveway. Indicate the position of the Sun, the eight planets, and the asteroid belt. Take photos of each and submit along with this report. (Your model should show the size of the orbits to scale but does not have to include scale models of the planets themselves.) 1. Calculate the two scale factors that will be required to fit the Solar System on your kitchen table and onto your driveway. Show all necessary conversions. length of your kitchen table: _________167 cm___________ distance from Sun to Neptune: _______4.49689728e14 cm_____________ scale necessary: 1-to-_______3.71367e-13 cm_____________
length of your driveway: _______25 ft _____________ distance from Sun to Neptune: _______ 1.47536e13 ft_____________ scale necessary: 1-to-____1.6945e-12 ft ________________ 2. Calculate the location of each of the following in your table top model: Object actual distance from Sun scaled distance in model Mercury 5.833872e12 cm 1.5709182560648000670511e22 cm Venus 1.0771632e13 cm 2.9005355887840997830551e22 cm Earth 1.4959584e13 cm 4.0282480672757996487121e22 cm Mars 2.27389944e13 cm 6.1230519674607997160365e22 cm Jupiter 7.778496e13 cm 20.945576747530001426867e21 cm Saturn 1.42716504e14 cm 38.430044672789996695883e21 cm Uranus 2.869286616e14 cm 77.262832077164006250314e21 cm Neptune 4.49689728e14 cm 167 cm
3. Calculate the location of each of the following in your driveway model: Object actual distance from Sun scaled distance in model Mercury 1.914e11 ft 1.129536736500400095906e22 ft 13.554440838e22 in Venus 3.534e11 ft 2.0855709648863998140200e22 ft 25.026851579e22 in Earth 4.908e11 ft 2.8964296252581998025732e22 ft 34.757155503e22 in Mars 7.4603e11 ft 4.4026556506343998975694e22 ft 52.831867808e22 in Jupiter 2.552e12 ft 1.506048982000600000575e21 ft 180.72587784e20 in Saturn 4.6823e12 ft 2.763233992328100185887e21 ft 3.3158807908e22 in Uranus 9.41367e12 ft 5.555426379463000330361e21 ft 6.6665116554e22 in Neptune 1.47536e13 ft 25 ft 300 in 4. At this scale, what would be the diameter of Earth? Would the Earth’s diameter be about the thickness of a dime, or the thickness of a strand of hair, or the size of a cell, or the size of an atom, or ??? Show all work and explain all reasoning. At this scale (tabletop), the diameter of the Earth is less than the thickness of a cell. (Diameter of earth in cm.) 1,247,199,994.8 / 3.71367e-13 (scale factor in cm for tabletop) = 3.358402859704800125229e21 (thickness of Earth in scale model) *A cell is about 10 microns, and at this scale earth is about 4 microns. https://www.bing.com/search? q=how+thick+is+a+human+cell&cvid=d1b4218c4c5c4946bf0912e3f04d5100&aqs=edge..69i57j 0l7j69i60.9556j0j1&pglt=41&FORM=ANNTA1&PC=HCTS At this scale (driveway), the diameter of the earth is about the thickness of the strand of hair! (Diameter of earth in ft) 40,918,635 / 1.6945e-12 (scale factor in ft for driveway) = 2.4147910888167998244569e19 (Thickness of earth in scale model)
*The typical thickness of strand of hair is 75 microns, and at this scale Earth is 73 microns. http://www.bacteria-world.com/how-big-micron.htm 5. At this scale, how far would our Moon be away from Earth? Show all work and explain all reasoning. The moon is 1.261155e+9 feet or 38,440,004,400 centimeters away from earth. 38,440,004,400 / 3.71367e-13 (scale factor in cm for tabletop) = 1.0350947822503999695698e22 (distance to moon from Earth in centimeters) 1.261155e+9 / 1.6945e-12 (scale factor in ft for driveway) = 7.4426379462968004219192e20 (distance to Moon from Earth in Feet) 6. At this scale, where would the Alpha Centauri system (our nearest neighbor star system) be located? Use Google Maps or a similar resource as needed. Show all work and explain all reasoning. Alpha Centauri system 1.30985157e17 ft or 3.9924275854e18 cm away from Earth. 3.9924275854e18 / 3.71367e-13 (scale factor in cm for tabletop) = 1.0750625622094001077045e22 (distance from Alpha Centauri system to Earth) 1.30985157e17 / 1.6945e-12 (scale factor in ft for driveway) = 7.7300181174388002958153e22 (distance from Alpha Centauri system to earth)
(scroll down) Insert photo of table top model here. Be sure all planets are visible.
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