Copy of Lab 4 _ The Human Arm
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1. What is the mass of the arm and an estimate of its uncertainty? Explain how you
estimated the uncertainty.
Angle ( )
◦
M
l
(kg)
M
t
(kg)
M
T
(kg)
δ
90
0
1.885
0.01
50
0
2.200
0.01
50
100
3.970
0.02
130
0
2.050
0.02
Table 4.1:
The table shows the values for the angle of the arm when lifted at a certain angle, the
mass of the load (M
l
), mass applied (M
t
), and the uncertainty of the mass applied ( M
T
).
δ
Using equation 11.4 m
T
d
1
sin(θ) - m
L
(d
1
+ d
2
+ d
3
) - m
A
(d
1
+ d
2
) = 0 where m
T
is the mass applied
(kg), m
l
is the mass of the load (kg), θ is the angle of the metal arm (
°),
and d
1
, d
2
, d
3
are the
given distances of the arm given in the lab manual. By isolating for m
A
, the mass of the arm is
obtained:
m
A
(1.885)(2.35𝑠𝑖?(90))
14.5
=
m
A
= 0.3055 kg
We calculate the value of the mass applied by taking the average of the maximum and minimum
values:
. We then obtain its uncertainty by taking the difference
1.885 + 1.895
2
=
1. 890 𝑘𝑔
between the two m
T
values and averaging them:
For that reason, m
T
1.895 − 1.885
2
= ± 0. 005.
=
. Accordingly, the uncertainty of the mass of the arm (m
A
) is:
(1. 890 ± 0. 005)
.
(0. 3055 ± 0. 005)
2. Using Eq. 11.4, what is the theoretical value of
𝑚
T
(no uncertainty required) that will
balance the arm for
𝜃
= 50
°
? Show your work. What is the experimental value (estimate its
uncertainty) and is it consistent with the theoretical value?
m
T
d
1
sin(θ) - m
L
(d
1
+ d
2
+ d
3
) - m
A
(d
1
+ d
2
) = 0
m
T
=
?𝐴(?1 + ?2) ?1𝑠𝑖?(50)
= 0.3055 * 14.5
2.35*𝑠𝑖?(50)
=
2. 460 𝑘𝑔
When isolating for m
T
, the mass applied is neglected because there was no mass attached to the
arm. Therefore, the theoretical mass value of m
T
that will balance the arm for
𝜃
= 50
°
is 2.460
kg. The experimental value for the mass applied is found to be 2.200 kg and its uncertainty is
obtained by averaging the difference between its maximum and minimum values:
Its uncertainty is then obtained by averaging the difference between
2.200 + 2.210
2
=
2. 205 𝑘𝑔.
the maximum and minimum values:
As a result, the experimental
2.210 − 2.200
2
= ± 0. 005.
value for m
T
is
Comparing the experimental and theoretical values of m
T
, it
(2. 205 ± 0. 005).
can be observed that there is a moderate agreement between them.The difference between the
values (2.460-2.205 = 0.255) which falls within the standard deviations of the theoretical value
proving there is an agreement between the values. Hence, the experimental value of m
T
is
consistent with its theoretical value with no mass load applied.
3. Show your work for calculating the force at the elbow joint (
??
) for
𝜃
= 50
°
and
𝑚𝐿
= 0
g. Do not include uncertainty.
To calculate the force at the elbow joint, equation 11.5 must be used:
F
x
= 0 and
F
y
= 0.
Σ
Σ
𝑇??𝑠(θ) = 𝐹???𝑠(θ)
gm
T
cos( ) = F
E
cos(
θ
ϕ)
1.889*9.81*cos(50
°
= F
Ex
)
F
Ex
= 11.90 N, to the left
F
y
= 0
-sin( )m
T
g - m
A
g - m
L
g - F
E
sin( ) = 0
θ
θ
F
Ey
= [-sin(50)*
2.2
9*9.81] -[ 0.3055*9.81 + 0*9.81]
F
Ey
= 16.50 N, downwards
Thus, F
E
=
𝐹?
2
+ 𝐹?
2
= (− 11. 90)
2
+ (− 16. 50)
2
= 20. 34𝑁. 4. Calculate and measure
𝑚𝑇
for 50
°
and a load (either 100 g or 150 g depending on your
setup). Calculate
??
(no uncertainty). You should include an estimate of the uncertainty for
the measured
𝑚𝑇
. How do these values compare to the answers without a load? Show your
work for all parts of this question.
Using equation 11.4, the theoretical mass applied can be isolated from the equation as follows:
m
T
=
?𝐿(?1+?2+?3) + ?𝐴(?1 + ?2) ?1𝑠𝑖?(50)
=
[0.1*0.29]+[0.3055*0.145]
0.0235*𝑠𝑖?(50)
=
4. 072 𝑘𝑔 However, the experimental mass obtained from the lab experiment is 3.970 kg. To calculate the
experimental value of m
T
, the average mass values are taken:
The
3.970+3.990
2
=
3. 980 𝑘𝑔.
uncertainty is then found by:
Hence, the experimental value of m
T
when
3.990−3.970
2
= ± 0. 01.
m
L
is 150 grams is
Comparing the theoretical and experimental values of m
T
,
(3. 980 ± 0. 01).
it is observed that the difference between the values (4.072 - 3.980 = 0.092) and the uncertainty
is (0.01 - 0 = 0.01), which does not fall within the standard deviation of the theoretical value,
showing that there is a slightly poor agreement between them. The experimental value of m
T
is
not consistent with its theoretical value due to the human error of miscalculating the weights
applied and not properly balancing the arm when the apparatus is at 50° with a load of 0.100 kg
applied.
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