Copy of Lab 4 _ The Human Arm

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University of Alberta *

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5555

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Mechanical Engineering

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Apr 3, 2024

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pdf

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4

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1. What is the mass of the arm and an estimate of its uncertainty? Explain how you estimated the uncertainty. Angle ( ) M l (kg) M t (kg) M T (kg) δ 90 0 1.885 0.01 50 0 2.200 0.01 50 100 3.970 0.02 130 0 2.050 0.02 Table 4.1: The table shows the values for the angle of the arm when lifted at a certain angle, the mass of the load (M l ), mass applied (M t ), and the uncertainty of the mass applied ( M T ). δ Using equation 11.4 m T d 1 sin(θ) - m L (d 1 + d 2 + d 3 ) - m A (d 1 + d 2 ) = 0 where m T is the mass applied (kg), m l is the mass of the load (kg), θ is the angle of the metal arm ( °), and d 1 , d 2 , d 3 are the given distances of the arm given in the lab manual. By isolating for m A , the mass of the arm is obtained: m A (1.885)(2.35𝑠𝑖?(90)) 14.5 = m A = 0.3055 kg We calculate the value of the mass applied by taking the average of the maximum and minimum values: . We then obtain its uncertainty by taking the difference 1.885 + 1.895 2 = 1. 890 𝑘𝑔 between the two m T values and averaging them: For that reason, m T 1.895 − 1.885 2 = ± 0. 005. = . Accordingly, the uncertainty of the mass of the arm (m A ) is: (1. 890 ± 0. 005) . (0. 3055 ± 0. 005) 2. Using Eq. 11.4, what is the theoretical value of 𝑚 T (no uncertainty required) that will balance the arm for 𝜃 = 50 ° ? Show your work. What is the experimental value (estimate its uncertainty) and is it consistent with the theoretical value? m T d 1 sin(θ) - m L (d 1 + d 2 + d 3 ) - m A (d 1 + d 2 ) = 0 m T = ?𝐴(?1 + ?2) ?1𝑠𝑖?(50) = 0.3055 * 14.5 2.35*𝑠𝑖?(50) = 2. 460 𝑘𝑔 When isolating for m T , the mass applied is neglected because there was no mass attached to the arm. Therefore, the theoretical mass value of m T that will balance the arm for 𝜃 = 50 ° is 2.460 kg. The experimental value for the mass applied is found to be 2.200 kg and its uncertainty is obtained by averaging the difference between its maximum and minimum values: Its uncertainty is then obtained by averaging the difference between 2.200 + 2.210 2 = 2. 205 𝑘𝑔. the maximum and minimum values: As a result, the experimental 2.210 − 2.200 2 = ± 0. 005.
value for m T is Comparing the experimental and theoretical values of m T , it (2. 205 ± 0. 005). can be observed that there is a moderate agreement between them.The difference between the values (2.460-2.205 = 0.255) which falls within the standard deviations of the theoretical value proving there is an agreement between the values. Hence, the experimental value of m T is consistent with its theoretical value with no mass load applied. 3. Show your work for calculating the force at the elbow joint ( ?? ) for 𝜃 = 50 ° and 𝑚𝐿 = 0 g. Do not include uncertainty. To calculate the force at the elbow joint, equation 11.5 must be used: F x = 0 and F y = 0. Σ Σ 𝑇??𝑠(θ) = 𝐹???𝑠(θ) gm T cos( ) = F E cos( θ ϕ) 1.889*9.81*cos(50 ° = F Ex ) F Ex = 11.90 N, to the left F y = 0 -sin( )m T g - m A g - m L g - F E sin( ) = 0 θ θ F Ey = [-sin(50)* 2.2 9*9.81] -[ 0.3055*9.81 + 0*9.81] F Ey = 16.50 N, downwards Thus, F E = 𝐹? 2 + 𝐹? 2 = (− 11. 90) 2 + (− 16. 50) 2 = 20. 34𝑁. 4. Calculate and measure 𝑚𝑇 for 50 ° and a load (either 100 g or 150 g depending on your setup). Calculate ?? (no uncertainty). You should include an estimate of the uncertainty for the measured 𝑚𝑇 . How do these values compare to the answers without a load? Show your work for all parts of this question. Using equation 11.4, the theoretical mass applied can be isolated from the equation as follows: m T = ?𝐿(?1+?2+?3) + ?𝐴(?1 + ?2) ?1𝑠𝑖?(50) = [0.1*0.29]+[0.3055*0.145] 0.0235*𝑠𝑖?(50) = 4. 072 𝑘𝑔 However, the experimental mass obtained from the lab experiment is 3.970 kg. To calculate the experimental value of m T , the average mass values are taken: The 3.970+3.990 2 = 3. 980 𝑘𝑔. uncertainty is then found by: Hence, the experimental value of m T when 3.990−3.970 2 = ± 0. 01. m L is 150 grams is Comparing the theoretical and experimental values of m T , (3. 980 ± 0. 01). it is observed that the difference between the values (4.072 - 3.980 = 0.092) and the uncertainty is (0.01 - 0 = 0.01), which does not fall within the standard deviation of the theoretical value, showing that there is a slightly poor agreement between them. The experimental value of m T is not consistent with its theoretical value due to the human error of miscalculating the weights applied and not properly balancing the arm when the apparatus is at 50° with a load of 0.100 kg applied.
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