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2-Methylbutane Lab Report

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This procedure substituted an alcohol functional group on an alkene with a chlorine, converting 2-methyl-2-butanol into 2-chloro-2-methylbutane. In this reaction, the alcohol group needs to be detached from the molecule for the chlorine to bind; thus the alcohol is called the leaving group. It does not constitute a good leaving group, since if it's departure took place, the resulting OH- would be a strong base. However, if exposed to a sufficiently acidic environment, the alcohol group could be protonated and become -H2O+, which is a much more effective leaving group. This leaving group can then be replaced by a nucleophile, but there are two different manners in which this may happen. The first involves a two-step process, where the leaving …show more content…

Since the neutralization reaction yields H2CO3, it's decomposition would produce carbon dioxide gas, which would bubble out of the solution. The neutralized solution was placed back into the funnel and the aqueous layer drained; after this washes with 10 mL of concentrated brine and 10 mL distilled water were performed to remove the NaCl and water produced during the neutralization out of the organic layer containing 2-chloro-2-methylbutane. The latter was then dried with anhydrous sodium sulfate, after which the percent yield of the liquid product was …show more content…

Although some product was lost during transfer of solutions and venting during extraction, the overall yield was acceptable. The silver nitrate and sodium iodide tests performed to ascertain the gross structure of the C-Cl bond and the IR signature obtained from analyzing the product both pointed to 2-chloro-2-methylbutane being the result of the protocol, as the halide tests indicated the chlorine was attached to a tertiary carbon and the IR indicated no -OH bonds or carbon-carbon double bonds, which would be indicative of an elimination reaction, were present in the molecule; thus the 2-chloro-2-methylbutane product was relatively

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