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Acid and Base

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Experiment 4:

ACIDS AND BASES: PH Measurements and Macroscale Titration

CHM023L – A12
Group no. 6 Members: | Contributions: | | Conclusion | | Recommendation | | Tables and figures with analysis | | Principles, Equation | | Abstract, tables |

Date Performed: February 28, 2012 - Tuesday
Date Submitted: March 6, 2012 - Tuesday
Submitted to:

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ABSTRACT:

This experiment introduces us the pH measurement and application of macroscale titration of aqueous solutions of acids and bases. The first part of the experiment was applying macroscale titration to calculate the mass of an HCl solution consumed that was initially done by pounding the tablets and getting a weight of 0.15 grams. …show more content…

The standard solution is added to a solution of unknown concentration until all of the unknown solution has reacted. From the known quantity and molarity (or normality) of the standard solution and the measured volume of unknown solution used, the unknown concentration can be calculated.

Most acid-base solutions are colorless and determining when one reactant has been totally consumed is difficult by simple observations. To allow us to visually determine this point, we use compounds called acid-base indicators to tell us when a reaction is complete. Dyes (usually weak organic acids) whose colors depend upon pH are often used to signal the completion of acid - base reactions.

The objectives of this experiment are to:
• Measure the PH of aqueous solutions of acids and bases.
• Compare the PH values obtained by using PH meter and PH paper.
• Calculate the percent acetic acid of a commercial sample of vinegar.

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EQUATIONS:

* The dissociation of water:
H2O ↔ H++ OH- * [H+] OH-= Kw=1 x 10-14 - (logH++log[OH-])= -log⁡ (1 x 10-14) -logH+-logOH-=14 pH+pOH=14 pH= -log[H+] pOH= -log[OH-] * Percent acetic acid in a vinegar:
% acetic acid =weight acetic acidweight of sample x 100 * Weight of acetic acid:
WCH3COOH=mLNaOH x MNaOH x 1 mol NaOH1000 milimole x 1 mole CH3COOH1 mol NaOH x 60 grams1 mol CH3COOH * Molarity:
Molarity= mmoles of solutemL of solution

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