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Cellulose And Caffeine Lab Report

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Introduction Tea contains cellulose, tannins, and caffeine. A tea leaf can contain up to 5% caffeine. Caffeine has a higher solubility in boiling water (67.0 g /100 g solvent) than in water at room temperature (2.26 g / 100 g solvent). Boiling removes cellulose. Caffeine is four times more soluble in dichloromethane (8.45 g /100 g solvent) at room temperature than water. The caffeine is extracted from the water at room temperature. The addition of an anhydrous basic salt would remove the water from the solution, and leave behind pure caffeine. Procedure Start by placing weighing two tea bags and recording in the report sheet. Add the two tea bags in a 250 mL Erlenmeyer flask. Add 60 mL of water inside the flask. Make sure to not poke the …show more content…

Circle and label (a) an amide functional group, (b) a tertiary amine, and (c) the purine ring system. The purine ring system Caffeine is an alkaloid and has base characteristics. Of the four nitrogens in the structure of the molecule, which one(s) would give it this property? The Nitrogen not connected to a methyl group displays basic properties. Besides caffeine, what else is extracted into the tea? Why can you use the basic salt, Na2CO3, sodium carbonate, to remove this material? Tannins can also be removed. By adding Na2CO3 can be used because it reacts and forms a salt that is insoluble in organic solvents but soluble in water. Tannins have acidic behavior. When a basic salt such as sodium carbonate is added to the water solution containing the tannins, the tannins react and form a salt. The produced salt in insoluble in organic solvent, but soluble in water. What criterion is used for the purity of a sample of caffeine? The criterion used is the evaporation of the dichloromethane it produces natural caffeine which is then purified by sublimation. However, the purity is determined by the difference of the melting point of the sample and the reference melting point for

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