ading Summary
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
Date Taken:
7/24/2014
Time Spent:
5 h , 44 min , 39 secs
Points Received:
20 / 26 (76.9%)
Number of Attempts:
0
Question Type:
# Of Questions:
# Correct:
Multiple Choice
15
12
Matching
1
1
Grade Details - All Questions
Question 1.
Question :
(TCO 3) Determine the Boolean expression at TP1 with respect to the corresponding inputs.
Student Answer:
Instructor Explanation:
TP1 is the output of an OR gate. The Boolean operator for the OR gate is + and the inputs are A and B. Refer to Chapter 3 of the textbook for more information.
Points
…show more content…
Points Received:
2 of 2 Comments:
Question 10.
Question :
(TCO 3) Determine the correct output waveform for the circuit below.
Student Answer:
YOptionA
YOptionB
YOptionC
YOptionD Instructor Explanation:
Y should be HIGH (when A = 0 AND B = 1) OR (when C NAND = 1). YOptionD is the only waveform that meets those criteria.
Points Received:
2 of 2 Comments:
Question 11.
Question :
(TCO 3) Determine the Boolean expression at TP1 with respect to the corresponding inputs.
Student Answer:
Instructor Explanation:
TP1 is the output of an XOR gate. The Boolean operator for the AND gate is and the inputs are A and B. Refer to Chapter 3 of the textbook for more information.
Points Received:
1 of 1 Comments:
Question 12.
Question :
(TCO 3) Determine the Boolean expression at TP2 with respect to the corresponding inputs.
Student Answer:
Instructor Explanation:
TP2 is the output of an XNOR gate. The Boolean operator for the XNOR gate is , the XNOR gate requires an inversion bar over the entire expression, and the inputs are C and. Refer to Chapter 3 of the textbook for more information.
Points Received:
1 of 1 Comments:
Question 13.
Question :
(TCO 3) Determine the VHDL assignment statement at X with respect to the inputs.
Student Answer:
X <= (A XOR B) OR NOT (NOT B OR C);
X <= (A XOR B) OR (NOT B NOR C);
X <= (A XOR B OR NOT B OR
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
6. (TCO 3) Which pseudocode produces the same result as the following? if customerAge > 65 OR customerAge = 65 then
When you do the math you come up with the “Binary Truth Line” which is :
address calculation of instructions - this determine the address of the next instruction to be processed.
Q#2 Write assembly code that illustrates the use of direct addressing mode , and use of the MUL function
Directions: In the space provided, write a (T), if you consider the statement TRUE (correct), or an (F), if you consider the statement to be FALSE (incorrect).
A storysack is a large cloth bag containing a children's picture book with supporting materials to stimulate
All the inputs of non - sure resources need to be addressed. survey, conducted depends on the method of data received by a input buffer (examining the constraints ) or reading from an integer ( checking and input signal ).
The third line is a response to the first two lines. The pattern is in the AAB form.
We can find this point at the graph, the highest point in the graph. And the corresponding output is the vertically downward on the horizontal axis.
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
if ((xintersec>seg1[0][0] and xintersec>seg1[1][0]) or (xintersec>seg2[0][0] and xintersec>seg2[1][0])) or ((xintersecseg1[0][1] and yintersec>seg1[1][1]) or (yintersec>seg2[0][1] and yintersec>seg2[1][1])):
The stimulant signals are fuzzified and symbolised in fuzzy set notations by membership routines. The specified ‘if … then …’ rules acquire the linguistic variables and these variables are defuzzified into assure signals for comparison with a carrier signal to yield PWM inverter pacing pulses. Fuzzy logic control implifies three steps: fuzzification, decision-making and defuzzification. Fuzzification modifies the non-fuzzy (numeric) stimulant variable evaluates into the fuzzy set (linguistic) variable that is a clearly specified edges. In the suggested controller, the energy exhausted and packet deprivation are specified by linguistic variables such as low, medium and high characterized by memberships. The memberships are curves that specify how each point in the stimulant space is represented to a membership assess between 0 and 1. The user port faculty of fuzzy logic is shown in figure 3.1. The membership routines consisting to the other stages are superposable Membership routines for the stimulants are shown in Fig.3.2 and Fig.3.3. The membership routine of production variable is shown in Fig.3.4. the surface viewer of our fuzzy logic is shown in figure 3.5. It is a three attribute delegacy of mapping of energy exhausted, packet deprivation and production of fuzzy logic. Because this curve symbolises a two-stimulant one-production case, you could see the entire mapping in one plot. Packet deprivation is along x axis and energy