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Ir Spectrum

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The percent yield for the reaction was rather low, 48.02%. This could be a result of a possible loss of product during the washing phase when releasing the gas. The loss of product could have occurred when trying to pipet the dried ester. The boiling point for the product was not taken. The H-NMR of the unknown alcohol was provided for analysis in order to determine the identity. Based on the peaks and their respective locations, the unknown was determined to be isopentanol. The peak at 0 ppm was the TMS. From this, the first doublet peak represented the six hydrogens located on the two terminal carbons, the signal was split as a result of the single hydrogen from the adjacent carbon. This peaks falls within the typical range for a primary alkyl hydrogen, 0.7-1.3 ppm. The next peak is a quartet that has a …show more content…

For the acetic acid spectrum, the broad peak ranging from 3300 cm-1 indicate the presence of a carboxylic O-H bond. The little bump at just under 3000 cm-1 indicates the presence of sp3 carbon hydrogen bonds. The peak at 1704.3 cm-1 shows the presence of a carbon oxygen double bond. For the isopentanol spectrum, the peaks located just under 3000 cm-1 indicate carbon hydrogen bonds. The broad peak ranging from 3300 cm-1 to 3200 cm-1 indicate the presence of an oxygen hydrogen alcohol bond present. For the product, the peaks located just under 3000 cm-1 indicate carbon hydrogen bonds. The peak located at 1739.58 cm-1 indicate the presence of a carbon oxygen double bond, more specifically an ester carbon oxygen double bond, because it falls in the typical range of 1735 cm-1 to 1750 cm-1. In this spectra however, there is no peak located in the region for an alcohol O-H bond or a carboxylic acid O-H bond. Based on these spectra, the data indicates that the that the esterification has occurred

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