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Limewater Test Lab Report

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1. Limewater Test: As we exhaled CO2 in the limewater solution, the CO2 reacted with Ca(OH)2 and changed the clear colorless limewater solution to precipitated white solution. The precipitation was caused due to the calcium in the limewater solution. It took us 5 attempts to turn the clear colorless limewater solution to a milky white solution. 2. Phenolphthalein Indicator Test: As phenolphthalein indicator was added to NaOH and H2O solution, it made the solution turn clear pink. The phenolphthalein indicator detects the presence of the base in the solution by changing the color of the solution from clear colorless to clear pink. As we exhaled into the pink solution, the CO2 reacted with the NaOH and H2O solution. This makes the solution …show more content…

Phenolphthalein Indicator Test: CO2 (g) + H2O(l) --> H2CO3(aq) H2CO3(aq) + 2NaOH(aq) --> Na2CO3(aq) + 2H2O(l) How would the results of both tests be affected if you performed the tests immediately after vigorously exercising for several minutes? Explain. Performing vigorous exercise requires a high demand of energy in order to be accomplished, the body adapts to this change by increasing the rate of aerobic cellular respiration which would produce more energy to meet the needs. As a result there would be much more carbon dioxide being exhaled from the body as it is one of the waste products produced during aerobic cellular respiration. CO2 is specifically formed during the Pyruvate oxidation and Kreb Cycle stage of the cellular respiration. To exemplify during pyruvate oxidation one of the steps is a decarboxylation reaction in which the carboxyl group of pyruvate is removed to from CO2. Overall for one glucose molecule two molecules of CO2 is released during pyruvate oxidation as glycolysis yields two pyruvate molecules. Furthermore the Krebs Cycle also produces CO2 molecules during the oxidation of isocitrate which produces a-ketoglutarate. Another CO2 molecule is also produced during the oxidation of a-ketoglutarate. This reaction produces the molecule succinyl CoA. As a result two CO2 molecules are produced for one acetyl-CoA. These points exemplify how the increase rate of cellular respiration would increase the rate of CO2 being exhaled. In connection to the lab investigation this would speed up the rate of reactions as there would be a much higher concentration of CO2 being exhaled compared to when the body is at rest. As a result this would increase the amount of product being produced because of the increase of CO2 in the reaction. Due to which the lab experiment would occur at a higher rate and it would be faster as

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