1: Design a circuit 10 Half-Wave Rectifier with Resistive Load to produce an average voltage of 40 V across a 100- load resistor from a 120-V ac source. Determine the power absorbed by the resistance and the power factor.
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- A half-wave rectifier is to provide an averagevoltage of 50 V at its output.a. Draw a schematic diagram of the circuit.b. Sketch the output voltage waveshape.c. Determine the peak value of the output voltage. d. Sketch the input voltage waveshape.e. What is the rms voltage at the input?Draw the circuit diagram of a half-wave rectifier for producing a nearly steady dc voltage from an ac source. Draw two different full-wave circuits.92) For three- phase half-wave Controlled rectifier Shown in the figure: I- Derive. a formula for mean load Voltage. 2- Draw the wave forms of vo, Li,i, o and voltage across thyristor1 (r.) assuming highly inductive loud and d = 120 Vo
- Fest For the controlled half-wave rectifier, the average voltage across a resistor 10052 load is 34 V from a 120-V rms 60-Hz Ac source. Determine a) The power absorbed by the resistance b) The RMS load Voltage and Current c) The power factor. I92) For three - phase half-wave Controlleed rectifier Shown in he figure: 1. Derive a fomu la for mean load Voltage. 2. praw the wave form of vo, i,,i, iy and voltage across thyristor 1 (r.) assuming highly inductive load and d = 120In the circuit in the figure, an AC voltmeter will be made with full wave rectifier circuit structure. R = 50ohm and diodesResistance values in the direction of transmission are Rd = 100ohm. Inside of the DC ammeter to be used as indicatorthe resistance is very, very small. The AC mark to be measured is Vs = 100 Sinwt Volts.a- Draw the shape of the current passing through the DC Ammeter and calculate its maximum value.b- Find the average value of the current passing through the DC Ammeter.c- Analyze the voltage seen at the ends of diode D1 for both alternans.d- Find the Rms value of the voltage seen at the ends of the diode D1.
- 3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL1.) The voltage on Figure Q1 is connected across a 0.15 2 resistive load. Calculate the power dissipated in this resistor. 2.) A 12 V rms ac supply is connected to the primary winding of a transformer with a turns ratio of 0.052. Calculate the rms secondary voltage given a voltage regulation of 4.0% 3.)Sketch the circuit for an ac supply input to a full-wave diode rectifier with a resistive load and no smoothing capacitor.The Figure 2 shows an electronic circuit designed for supplying power to a load (R1). The supply voltage 235V (RMS, AC) at frequency of 50HZ. The required DC voltage and power for the load are 24V and 3.6 W respectively. The Electrical Components of this AC to DC converter are: A full-wave rectifier to convert AC voltage to DC voltage. A regulator with transistor and Zener diode to ensure a constant voltage and power for the load. D1 Iide 91 Vaut VLoad D2 D3 Vde VI sine R1 RL Regulate Reetifier Figure 2. Complete Circuit Assume that the diodes are real diodes (NOT ideal diodes). The following information is available: The collector to base resistor of the regulator R1 = 5.0 k The transistor Q1 with B value of 24 is used for the regulator circuit. Determine the following quantities for this electronic device and fill the table below: Question Answer The voltage of Zener Diode (Vz) The current in R1 The DC current into the regulator | (Idc) Base current of transistor (IB) Collector…
- Calculate the rms load current for the single phase uncontrolled half-wave rectifier when the source voltage of 200V at a frequency of 50Hz, and load resistance is 10ohm.Design a single-phase full wave bridge rectifier with input voltage of 100v and inductive load of 10ohm and 40mH a. Show the waveform relation between the I/P and O/P b. Calculate the average O/P voltage c. Calculate the rms currentA full-wave rectifier uses 2 diodes. The internal resistance of each diode is 20 Q. The transformer RMS secondary voltage from centre tap to each end of the secondary is 50 V and the load resistance is 980 Q. Mean load current will be