1 #include 2 #include 3 using namespace std; 4 5 int main() { const int NUM VALS vector courseGrades (NUM_VALS); int i; 43B %3D 6. for (i cin >> courseGrades.at(i); 10 e; i < courseGrades.size(); ++i) { 11 12 13 14 /* Your solution goes here 15 16 return 0; 17 }
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- Vectors Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid vector element, such as courseGrades.at(9) for a 4-element vector, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> courseGrades(NUM_VALS);int i; for (i = 0;…Arrays: create an array of a given type and populate its values. Use of for loop to traverse through an array to do the following : to print the elements one by one, to search the array for a given value. ArrayList: create an ArrayList containing elements of a given type . Use some of the common ArrayList methods to manipulate contents of the ArrayList. Write methods that will take an ArrayList as its parameter/argument ; and/or return an ArrayList reference variable as its return type. Searching for an object in an Array: Loop through the ArrayList to extract each object and to check if this object’s attribute has a given value. Explain how and why interfaces are used in Java Collection Framework. Explain the major differences between a Stack and a Queue. Be able to use stack and queue methods. What is meant by O(N) notation? Express the complexity of a given code using the O(N) notation.numMembers is read from input as the size of the vector. Then, numMembers elements are read from input into the vector bikingRoster. Use a loop to access each element in the vector and if the element is less than averageMembers, output the element followed by a space. Ex: If the input is 8 193 102 3 86 38 161 169 153, then the output is: Average: 113 Numbers less than average: 102 3 86 38 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 unsigned int i; 8 double averageMembers; 9 int sumElementData = 0; 10 11 12 13 14 15 16 int numMembers; cin >> numMembers; vector bikingRoster (numMembers); for (i = 0; i > bikingRoster.at(i); sumElement Data + bikingRoster at(i):
- 19. A two-dimensional array is frequently called a matrix and such a matrix is usually displayed in a row X col format. Write a method, which displays a 3 X 4 matrix to the monitor, in a format like: sample data: 10 11 12 13 14 15 16 17 18 19 20 21 Complete method displayMatrix below. // precondition: // postcondition: 11 mat is a non-empty 2D array of int values. displayMatrix displays the elements of 2D array mat in Row X Col format. public static void displayMatrix(int[][] mat)Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.Checkpoint 1: Create an array and initialize all the elements to 0. Write a loop that will display cach elements position and value. That is show "my_arrayf3] = 0" for each element as output where 3 is the 4th clement in the array and 0 is value of that element. Now assign random values to cach element. You can use the function rand() which will return an integer. This function will return a number between 0 and RAND MAX = 32767. You can mod the value retumed by rand() by 16 to fit the range 0 to 15. For debugging, the seed is the same until you change it. This means all the output numbers will be the same as in the sample output. Checkpoint 2: We want to calculate some base statistics for the array. You can access each element of the array by using "my array[i]" where i is the index of the array. You may use a loop to run through each index to cover the entire array. We will start finding statistics for this array by finding the maximum value, minimum value, and sum of all values in…
- 3. A=[8 3 4 11 5 6 13 7 9] create a new vector named B by referencing to the elements of A from 4 to 8? Your answer← 10:15 docs.google.com Module 6: Vectors 11. Write code to create a std::vector of customers using the default constructor. Each element represents the number of visitors per hour. Specifically, the first element contains the number of visitors in the first hour of operation, the second element for the second hour, and so on. Log the number of visitors in this order: 2, 4, 1, 4, 3, 2, 1, 1. Get the total number of times visitors were logged and store it in a variable called hours_logged. For example, if visitor counts were added to the vector twice, then hours_logged would be 2. Get the number of visitors in the fourth hour and store it in a variable called midday_visitors. int main() { std::cout << "Logged hours: " << hours_logged << "\n"; std::cout << "Visitors in the middle of the day: "<< midday_visitors << "\n"; return 0; STOP HERE AND WAIT FOR FURTHER INSTRUCTIONS 98 Model 3. std::vector initialization (6 min) Start time: Line Code I VisualizationTradng SelCLOon Write the state of the elements of the vector below after each of the first 3 passes of the outermost loop of the selection sort algorithrm // index 0 1 2 3 4 5 6 7 Vector numbers = {29, 17, 3, 94, 46, 8, -4, 12}; selectionSort(numbers); For example, if the vector was {(43125), you would write: {4 3 1 2 5} {1 3 4 2 5} (1 2 4 3 5} {1 2 3 4 5} Thought: How many vectors would I need here if I were to implement this in code? Write your answer here. hp
- mu = 0 # mean sig = 1 # std # TODO 1.2 x_values = display(x_values) todo_check([ (x_values.shape == (120,),'x_values does not have the correct shape of (120,)'), (np.all(np.isclose(x_values, np.array([-4.…1. Declare an array to save 4 Dog objects. The Dog class is provided below. Look into the Dog class and find what attributes are needed for a dog object. Then initialize five dogs with the following information: Lily, 5 years old Jacob, 2 years old Sugar, 8 years old Bush, 3 years old 2. Print out every dog using a for loop (use either regular for loop or for-each loop, your choice). But you may find when you print out, the name and age are not displayed. Why? 3. Fix this problem by implementing the toString method in the Dog class. Dog Class: public class Dog { private String name; private int age; public Dog(String name, int age) { this.name = name; this.age = age; } public void setName(String name) { this.name = name; } }Parameters array - Any JavaScript Array size - A positive integer Number indicating the desired "chunk" size. Return Value A new Array of Arrays. Each sub-Array has a length equal to size. Remaining elements are gathered into a final sub-Array. Do not mutate the input array Do not use Array.prototype.slice in your implementation.Do not use Array.prototype.shift in your implementation.Do not use Array.prototype.pop in your implementation.Do not use Array.prototype.splice in your implementation. Please fix this JavaScript function so that the when calling the function with the parameters chunk([false, true, false, true], 3); the output is [[false, true, false], [true]] (subarrays)and when the parameters are chunk([undefined, null, 0, false, NaN, ""], 3); the output is [[undefined, null, 0], [false, NaN, ""]] thank you very much! function chunk(ar, sz) { var res = []; var ind = 0; // itterating through the new length of resulting array for (var i = 0; i < ar.length / sz; i++)…