1) The activation energy for the following first-order reaction is 102 kJ/mol. N₂O5(g) → 2NO2(g) + (1/2)0₂(g) The value of the rate constant (k) is 1.35 x 10-4 s-¹ at 35°C. What is the value of k at 0°C? (R= 8.314 J/mol-K) A. 8.2 x 10-7 s-1 B. 1.9 x 10-5 S-1 C. 4.2 x 10-5 sS-1 D. 2.2 x 10-² S-1

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General Chemistry for Engineers

Lesson: Chemical Kinetics 

Directions: Answer the following problems by showing the complete solution. In return, I will give you a good and high rating. Thank you so much!

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No. 1-2.

 

2) Enzymes are
A. large carbohydrates molecules
B. also called substrates
C. usually heterogeneous catalyst
D. insensitive to temperature
E. biological catalyst
Transcribed Image Text:2) Enzymes are A. large carbohydrates molecules B. also called substrates C. usually heterogeneous catalyst D. insensitive to temperature E. biological catalyst
1) The activation energy for the following first-order reaction is 102 kJ/mol.
N2O5(g) → 2NO2(g) + (1/2)O2(g)
The value of the rate constant (k) is 1.35 x 10-4 s-¹ at 35°C. What is the value of k at 0°C?
(R= 8.314 J/mol-K)
A. 8.2 x 10-7 s-1
B. 1.9 x 10-5 S-1
C. 4.2 x 10-5 S-1
D. 2.2 x 10-2 s-1
Transcribed Image Text:1) The activation energy for the following first-order reaction is 102 kJ/mol. N2O5(g) → 2NO2(g) + (1/2)O2(g) The value of the rate constant (k) is 1.35 x 10-4 s-¹ at 35°C. What is the value of k at 0°C? (R= 8.314 J/mol-K) A. 8.2 x 10-7 s-1 B. 1.9 x 10-5 S-1 C. 4.2 x 10-5 S-1 D. 2.2 x 10-2 s-1
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