10. Create a B-tree index on the customer’s Lastname column. Verify that the index exists by querying the data dictionary. Remove the index from the database
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10. Create a B-tree index on the customer’s Lastname column. Verify that the index exists by
querying the data dictionary. Remove the index from the
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- Create a B-tree index on the customer’s Lastname column. Verify that the index exists by querying the data dictionary. Remove the index from the database. (refer to the tables in the JustLee Books database).SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expressionselect * from cast where cast_id=162652763; Use explain to display the query plan without creating any index. Now create an index to speed up the query. Use explain and timer to show the improvement.
- 4. Update the name of the student to "John Doe" where its id is 10. Enter your answer 5. Modify the "student" table by adding "address" column/field as string and allows null.2. Get the Groups As new students begin to arrive at college, each receives a unique ID number, 1 to n. Initially, the students do not know one another, and each has a different circle of friends. As the semester progresses, other groups of friends begin to form randomly. There will be three arrays, each aligned by an index. The first array will contain a queryType which will be either Friend or Total. The next two arrays, students1 and students2, will each contain a student ID. If the query type is Friend, the two students become friends. If the query type is Total, report the sum of the sizes of each group of friends for the two students.Why it's useful to have index that partially sort a query if it doesn't present all of the results already sorted?
- individual characters using their 0-based index. Hint: You will need to do this for checking all the rules. However, when you access a character .Alternate keys: Identify at least five keys (not already listed as PK or FK) needed by end users. These indexes would be considered Alternate or Secondary keys and are mostly used for queries and quick reporting. They may contain multiple columns.9. Write a trigger that prohibits duplicate values except for nulls in the NoDupName column of the following table: CREATE TABLE TestUniqueNulls (RowID NoDupName varchar(20) int IDENTITY NOT NULL, NULL); (Note that you can’t do this by using a unique constraint because the constraint wouldn’t allow duplicate null values.) If an INSERT or UPDATE statement creates a duplicate value, roll back the statement and return an error message. Write a series of INSERT statements that tests that duplicate null values are allowed but duplicates of other values are not.
- Sales Database: Customers(custId, lastName, firstName, address, phone, creditLimit) Orders(ordNumber, itemNumber, qtyOrdered.) Items(itemNumber, itemName, price) For the Sales Database referenced above, write the SQL command to create the LineItem table, assuming the Orders table and items table already exist.create database GA2gouse GA2gocreate table salesman(salesman_id int primary key, name varchar(30), city varchar(20), commission varchar(30));insert into salesman (salesman_id, name, city, commission) values (5001, 'James Hoog', 'New York', 0.15); insert into salesman (salesman_id, name, city, commission) values (5002, 'Nail Knite', 'Paris', 0.13); insert into salesman (salesman_id, name, city, commission) values (5005, 'Pit Alex', 'London', 0.11); insert into salesman (salesman_id, name, city, commission) values (5006, 'Mc Lyon', 'Paris', 0.14); insert into salesman (salesman_id, name, city, commission) values (5007, 'Paul Adam', 'Rome', 0.13); insert into salesman (salesman_id, name, city, commission) values (5003, 'Lauson Hen', 'San Jose', 0.12); Create table Customer (customer_id int primary key, cust_name varchar(30), city varchar(10), grade varchar(30), salesman_id int,CONSTRAINT FK_salesman_id FOREIGN KEY (salesman_id) REFERENCES salesman(salesman_id));insert into customer…create database GA2gouse GA2gocreate table salesman(salesman_id int primary key, name varchar(30), city varchar(20), commission varchar(30));insert into salesman (salesman_id, name, city, commission) values (5001, 'James Hoog', 'New York', 0.15); insert into salesman (salesman_id, name, city, commission) values (5002, 'Nail Knite', 'Paris', 0.13); insert into salesman (salesman_id, name, city, commission) values (5005, 'Pit Alex', 'London', 0.11); insert into salesman (salesman_id, name, city, commission) values (5006, 'Mc Lyon', 'Paris', 0.14); insert into salesman (salesman_id, name, city, commission) values (5007, 'Paul Adam', 'Rome', 0.13); insert into salesman (salesman_id, name, city, commission) values (5003, 'Lauson Hen', 'San Jose', 0.12); Create table Customer (customer_id int primary key, cust_name varchar(30), city varchar(10), grade varchar(30), salesman_id int,CONSTRAINT FK_salesman_id FOREIGN KEY (salesman_id) REFERENCES salesman(salesman_id));insert into customer…