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12. The function f(x) = 0.5x² - 2x - 1 is shown graphed below. The function h(x) is defined by the formula h(x) = f(x) + 4. Answer the following questions. 0.5x2 (a) What is the value of h(2)? Justify. [2 points] 26+5 0.5X +3 F(x) y 10+ f(x) = 0.5x² -2x-1 (b) Graph h(x) on the same graph grid. [2 points] -2 (c) Give a formula for h(x) in terms of x. [2 points] 0.5x2-2x+5 -5- 5. +x -10 (d) How many solutions does the equation h(x) = 0 have? Justify your answer. [3 points] 3

12. The function f(x) = 0.5x² - 2x - 1 is shown graphed below. The function h(x) is defined by the formula h(x) = f(x) + 4. Answer the following questions. 0.5x2 (a) What is the value of h(2)? Justify. [2 points] 26+5 0.5X +3 F(x) y 10+ f(x) = 0.5x² -2x-1 (b) Graph h(x) on the same graph grid. [2 points] -2 (c) Give a formula for h(x) in terms of x. [2 points] 0.5x2-2x+5 -5- 5. +x -10 (d) How many solutions does the equation h(x) = 0 have? Justify your answer. [3 points] 3

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.4: More Quadratic Functions And Applications
Problem 55PS
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Answer D) How many solutions does the equation h(x)=0 have? Justify your answer.
12. The function f(x) = 0.5x² - 2x - 1 is shown graphed below. The function h(x) is defined by the formula h(x) = f(x) + 4. Answer the following questions. 0.5x2 (a) What is the value of h(2)? Justify. [2 points] 26+5 0.5X +3 F(x) y 10+ f(x) = 0.5x² -2x-1 (b) Graph h(x) on the same graph grid. [2 points] -2 (c) Give a formula for h(x) in terms of x. [2 points] 0.5x2-2x+5 -5- 5. +x -10 (d) How many solutions does the equation h(x) = 0 have? Justify your answer. [3 points] 3
Transcribed Image Text:12. The function f(x) = 0.5x² - 2x - 1 is shown graphed below. The function h(x) is defined by the formula h(x) = f(x) + 4. Answer the following questions. 0.5x2 (a) What is the value of h(2)? Justify. [2 points] 26+5 0.5X +3 F(x) y 10+ f(x) = 0.5x² -2x-1 (b) Graph h(x) on the same graph grid. [2 points] -2 (c) Give a formula for h(x) in terms of x. [2 points] 0.5x2-2x+5 -5- 5. +x -10 (d) How many solutions does the equation h(x) = 0 have? Justify your answer. [3 points] 3
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