17-61. If a horizontal force of P = 100 N is applied to the 300-kg reel of cable, determine its initial angular acceleration. The reel rests on rollers at A and B and has a radius of gyration of ko = 0.6 m. 0.75 m 20° 20°
Q: F19-1. The 60-kg wheel has a radius of gyration about its center O of ko = 300 mm. If it is…
A: Given Data: The mass of the wheel is m = 60 kg. The radius of gyration of the wheel is ko = 300 mm.…
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Q: Specifically a dynamics problem. Question in pic below. Answer: omega = 14.1 rad/s
A: The mass of inertia of the system is given as the Where, Irod and Iring is moment of intertia of…
Q: 17-105. If the coefficient of static friction between the 50-lb roller and the ground is u, = 0.25,…
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Q: 17-75. The wheel has a mass of 25 kg and a radius of gyration kg = 0.15 m. It is originally spinning…
A: Given data as per the question Mass of wheel = 25 kg Radius of gyration = 0.15 m Considering free…
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A: The weight of the wheel is W=100 lb. The radius of gyration of the wheel is kG=0.75 ft. The tension…
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Q: 18-42. The spool has a mass of 20 kg and a radius of gyration of ko = 160 mm. If the 15-kg block A…
A: Given Data: The mass of spool is m = 20 kg. Radius of gyration of spool is kO = 160 mm. Mass of…
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A: Sketch the FBD for the above problem.
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A: Given data as per the question Mass of crate =100 kg coefficient of friction =0.40
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Q: *17-100. A force of F = 10 N is applied to the 10-kg ring as shown. If slipping does not occur,…
A: The free-body diagram pf the ring is drawn as shown in the bellow figure. mass moment of inertia is…
Q: 17-57. The 10-kg wheel has a radius of gyrationk, = 200 mm. If the wheel is subjected to a moment M…
A: given mass of wheel (m) = 10 kg radius of gyration (kA) = 200 mm = 0.2 m Moment (M) = (5t) N-m To…
Q: 17-55. The 100-kg uniform crate C rests on the elevator floor where the coefficient of static…
A: Write the given data: m = 100 kgμs = 0.4r = 1.5 mW = mgW = (100 kg) (9.81 m/s2)W = 981 N
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A: Consider the diagram shown below for the given system.
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A: Given Data: The length of the rod is L = 3m. The mass of the rod is m = 30 kg. The number of…
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Q: If a horizontal force of P = 100 N is applied to the 300-kg reel of cable, determine its initial…
A: Horizontal force P=100 N Weight of reel of cable M=30 kgRadius of gyration ko=.6 m
Q: 19-53. The wheel has a mass of 50 kg and a radius of gyration of 125 mm about its center of mass G.…
A: Consider ω2 as the angular velocity of the wheel before the impact, ω3 as the angular velocity of…
Q: 17-75. The wheel has a mass of 25 kg and a radius of gyration kg = 0.15 m. It is originally spinning…
A: Find the moment of inertia of the wheel about the point B: I=mkB2I=25 kg0.15 m2I=0.5625 kg-m2 Draw…
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A: The angular velocity of the C can be expressed as, The velocity of the mass A can be calculated as,
Q: This is a Dynamics question. Answers: aG = 11.2 ft/s2, alpha = 7.45 rad/s2
A: Given data as per question Force = 30 lb Roller weight =50 lb Considering free body diagram
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Q: 18-3. The wheel is made from a 5-kg thin ring and two 2-kg slender rods. If the torsional spring…
A: mw = 5 kg mr = 2 kg r = 0.5 m l = 2r = 1m k = 2 Nm / rad Moment of Inertia about an axis…
Q: *18-12. Determine the velocity of the 50-kg cylinder after it has descended a distance of 2 m.…
A: The moment of inertia of the reel is written as, I=mkA2=25 kg125 mm×1 m1000 mm2=0.39 kg·m2…
Q: This is a Dynamics question. Answers: alpha = 14.7 rad/s2 Ax = 88.3 N…
A: Given data as per question Weight of plate = 24 kg Dimensions of the plate = 0.5 × 0.5 m
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Q: This is a Dynamics question. Answers: ax = 21.47 ft/s2, ay = 26.45 ft/s2,…
A: Given data as per question Mass of the beam = 150 lb considering free body diagram
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A: Given data: Mass of the ring, mr = 5 kg. Mass of the slender rod, ms = 2 kg. The radius of the…
Q: 17-119. The spool has a mass of 100 kg and a radius of gyration of kg = 200 mm about its center of…
A:
Q: 200 mm
A: Draw a diagram for the problem. Write the formula for mass moment of inertia of the spool.…
Q: Specifically a dynamics problem. Question in pic below. Answer: vA = 1.40 m/s
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A: Given : Mass of spool = 100 kg The radius of gyration = 0.3 m The coefficient of static friction =…
Q: *17-116. The disk of mass m and radius r rolls without slipping on the circular path. Determine the…
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Q: 19-21. The spool has a weight of 30 lb and a radius of gyration ko = 0.45 ft. A cord is wrapped…
A: mass of spool (m)=13.6078 kg ;weight of spool (W)=133.447 N ;load or force( P)=5 lb= 22.241 N…
Q: ation 5 The 20-kg wheel has a radius of gyration ko - 400 mm where O is the center of the wheel. If…
A:
Q: 18-6. A force of P=20 N is applied to the cable, which causes the 175-kg reel to turn without…
A: p = 20 N kG = 0.42 m r =0.1 m
Q: F17-15. The 20-kg wheel has a radius of gyration about its center O of ko = 300 mm. When the wheel…
A: Given data as per the question Mass of wheel =20 kg The radius of gyration =300 mm Coefficient of…
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A: Given data: Mass of the wheel, m = 50 lb. The radius of gyration about the center of gravity, kG=…
Q: *18-12. Determine the velocity of the 50-kg cylinder after it has descended a distance of 2 m.…
A: Given Mass of the cylinder, M = 50 kg Mass of the reel, m = 25 kg Find Velocity, v
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A: Given : The mass of wheel = 100 kg The radius of gyration = 0.3 m The radius of the wheel = 400 mm=…
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A: Make FBD for the given shapes
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- The 214-kg wheel has a radius of gyration about its center O of ko = 260 mm, and radius r = 0.4 m. When the wheel is subjected to the constant couple moment M = 94 N•m, it starts rolling from rest. Determine the average friction force that the ground applies to the wheel if it has been rolling without slipping. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper Sl unit. Take g = 9.81 m/s². M Your Answer: Answer unitsAL 0.6 m A B 500 mm 19-10. The frame of the roller has a mass of 5.5 Mg and a center of mass at G. The roller has a mass of 2 Mg and a radius of gyration about its mass center of kA = 0.45 m. If a torque of M = 600N m is applied to the rear wheels, determine the speed of the compactor in t = 4 s, starting from rest. No slipping occurs. Neglect the mass of the driving wheels. Ⓡ 1.95 m C Prob. 19-9 0.86 m 200 mm Gj B Prob. 19-10 1.10 m 43 44 B GA M 0.5 mThe 186-kg wheel has a radius of gyration about its center O of ko = 300 mm, and radius r = 0.4 m. When the wheel is subjected to the constant couple moment M = 92 N.m, it starts rolling from rest. Determine the average friction force that the ground applies to the wheel if it has been rolling without slipping. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper Sl unit. Take g = 9.81 m/s². M Your Answer: units Answer
- The 27-kg wheel has a radius of gyration about its center O of ko = 260 mm, and radius r = 0.5 m. When the wheel is subjected to the constant force F = 354 N, applied to the wheel's center axle at an angle = 6°, it starts rolling from rest. Determine the wheel's angular velocity W (in rad/s) after 3.2 seconds if the wheel has been rolling without slipping. Please pay attention: the numbers may change since they are randomized. Your answer must include 1 place after the decimal point. Take g = 9.81 m/s². F 0 Your Answer: Answer*18–4. The wheel is made from a 5-kg thin ring and two 2-kg slender rods. If the torsional spring attached to the wheel's center has a stiffness k = 2 N•m/rad, and the wheel is rotated until the torque M = 25 N • m is developed, determine the maximum angular velocity of the wheel if it is released from rest. 0.5 m MThe 21-kg wheel has a radius of gyration about its center O of ko =260 mm, and radius r = 0.5 m. When the wheel is subjected to the constant force F = 247 N, applied to the wheel's center axle at an angle = 6°, it starts rolling from rest. Determine the wheel's angular velocity W (in rad/s) after 4.0 seconds if the wheel has been rolling without slipping. Please pay attention: the numbers may change since they are randomized. Your answer must include 1 place after the decimal point. Take g = 9.81 m/s². Your Answer: G Answer r 0 F
- 18-2. The wheel is made from a 5-kg thin ring and two 2-kg slender rods. If the torsional spring attached to the wheel's center has a stiffness k = 2 N- m/rad, and the wheel is rotated until the torque M = 25 N •m is developed, determine the maximum angular velocity of the wheel if it is released from rest. 0.5 m мIf a horizontal force of P = 100 N is applied to the 300-kg reel of cable, determine its initial angular acceleration. The reel rests on rollers at A and B and has a radius of gyration of ko = 0,6 m. 0.75 m Select one: O A. a = 0.588 rad/s2 O B. a = 0.694 rad/s2 OC. a = 0.789 rad/s a = 0.656 rad/s2F18–1. The 80-kg wheel has a radius of gyration about its mass center o of ko = 400 mm. Determine its angular velocity after it has rotated 20 revolutions starting from rest. 0.6 m P = 50 N
- if mass (m)=345kg radius of gyration kG = 0.54 m θ= 200 degree 1) assuming no slipping and when starting from horizontal cable (θ = 0o) the spool moves to the left- determine the minimum tension in the cable (Tmin) that causes the spool to slip. Assumeμk = 0.4 and μs = 0.5.stion 5 The 20-kg wheel has a radius of gyration ko = 400 mm where O is the center of the wheel. If the wheel is subjected to a moment, M = (2t) N.m, where t is in seconds, determine its angular velocity when t- 4s starting from rest. Assume the wheel is subjected to rotation only (no translation). OA 16.0 rad/s B. 10.0 rads oc 8.0 rad/s 0 5.0 rad/sf cion A force of P = 20 N is applied to the cable, which causes a 175 kg of radius of Gyration KG = 0.42m reel to turn without slipping on the 2 rollers A and B of each 18 kg and radius of 0.1m. P 30° 250 mm OG 500 mm AO OB -400 mm- Calculate the work done by the 20N for 2 revolutions. (J) Determine the angular velocity of the reel after it has rotated 2 revolutions starting from rest. (rad/s) Calculate the Kinetic energy of roller A after the reel rotated 2 revolutions starting from rest. (J) Choose... 7.952 1.88 32.2 3.14 1.98 16.34 20 3.66 62.831 Choose... Choose... Choose... 52 8:44 AM MM