2/ According to the following reaction, how many moles of nitrogen monoxide will be formed upon the complete reaction of 0.636 moles nitrogen gas with excess oxygen gas? nitrogen (g) + oxygen (g)-nitrogen monoxide (g) moles nitrogen monoxide 6 D Use the References to access Important values if needed for this question. Submit Answer = ✓ ✓ ✓ A 6 0 Done According to the following reaction, how many moles of ammonia will be formed upon the complete reaction of 0.862 moles' ammonium chloride? ammonium chloride (aq) ammonia (g) + hydrochloric acid (aq) moles ammonia 0

2/ According to the following reaction, how many moles of nitrogen monoxide will be formed upon the complete reaction of 0.636 moles nitrogen gas with excess oxygen gas? nitrogen (g) + oxygen (g)-nitrogen monoxide (g) moles nitrogen monoxide 6 D Use the References to access Important values if needed for this question. Submit Answer = ✓ ✓ ✓ A 6 0 Done According to the following reaction, how many moles of ammonia will be formed upon the complete reaction of 0.862 moles' ammonium chloride? ammonium chloride (aq) ammonia (g) + hydrochloric acid (aq) moles ammonia 0

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
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Data Mass of unknown metal Cark te ?l.005g Volume of uniknown solotion CmL) Volume of HCI added Inital burct readinglmL) Final buret reading (mL) 20.00ML (mL) 15.00mL 20.SSmL 30.90ML Volume Na OH delivered (m L) Concentration of HCI: O.1708M Concentrahon of NaOH: O.1000M * Pipetted 10.35mL 20.00mL Of solution prepared in 250.0 mL volumetric flask Questions', 1. Calalate the number of moles of Na OH used for back titration? 2. Calculate the number of moles moles of metal carbonate present in 20.00mL portion of the metal Carborate soltion? 3. Calculate molar masS of 3.Calculate in knon metal carbongte