2 is corrosive, so purging with N2. which is inert, helps to reduce reactivity within the spectrometer. 2 has 7 absorption bands in the infrared spectrum while N2 only has 1. Since it's better to have fewer bands in the spectrum, N2 is used to lace CO2. 2 is not IR active, so it does not have a spectral band. It is important to have an IR active gas in the spectrometer, so N2. which is IR active, is ed. is IR active, which means it has a spectral band that can interfere with other spectral features. N, is not IR active, so purging with this gas

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter25: Instruments For Optical Spectrometry
Section: Chapter Questions
Problem 25.6QAP
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QUESTION 5
When acquiring an infrared spectrum, it is common to purge the instrument with nitrogen. This minimizes the presence of CO within the instrument.
Which of the following statements is true?
O co, is corrosive, so purging with N,, which is inert, helps to reduce reactivity within the spectrometer.
O co, has 7 absorption bands in the infrared spectrum while N, only has 1. Since it's better to have fewer bands in the spectrum, N, is used to
replace CO2.
O co, is not IR active, so it does not have a spectral band. It is important to have an IR active gas in the spectrometer, so N2, which is IR active, is
added.
O co, is IR active, which means it has a spectral band that can interfere with other spectral features. N, is not IR active, so purging with this gas
would not result in any additional spectral bands.
Transcribed Image Text:QUESTION 5 When acquiring an infrared spectrum, it is common to purge the instrument with nitrogen. This minimizes the presence of CO within the instrument. Which of the following statements is true? O co, is corrosive, so purging with N,, which is inert, helps to reduce reactivity within the spectrometer. O co, has 7 absorption bands in the infrared spectrum while N, only has 1. Since it's better to have fewer bands in the spectrum, N, is used to replace CO2. O co, is not IR active, so it does not have a spectral band. It is important to have an IR active gas in the spectrometer, so N2, which is IR active, is added. O co, is IR active, which means it has a spectral band that can interfere with other spectral features. N, is not IR active, so purging with this gas would not result in any additional spectral bands.
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