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- 2. A mixture of two enantiomers has as observed rotation of -18°. The specific rotation of the (-)enantiomers is -27°. Find the % of the two enantiomers in the solution.2. After an attempt to resolve a racemate into its enantiomers, the observed rotation is +22.4 degrees per g/L. If the known specific rotation is +24.2 degrees per g/L,, what is the % enantiomeric excess of the compound?Consider a mixture that is 60% (+) enantiomer and 40% (-) enantiomer. In which direction will the mixture rotate plane-polarized light? What is the enantiomeric excess of the mixture?
- Consider a mixture that is 38% (+) enantiomer and the rest is the (-) enantiomer. a) In which direction would the mixture rotate plane-polarized light? Briefly explain. b) What is the %ee of the mixture? Briefly explain or draw a pie chart like those done in class. c) If the (+) enantiomer has a specific rotation of +28.5°, what is the specific rotation of the mixture? Show whork.4. The [a] of pure quinine, an antimalarial drug, is -165°. a) Calculate the enantiomeric excess (EE) of a solution with the following [a] values: -83°. H3CO HO Hin Quinine (anti-malaria drug) b) Calculate the percent of each enantiomer present. c) What is [a] for the enantiomer of quinine, and does it rotate light clockwise or counterclockwise? ( d) Identify 2 functional groups in quinine. (.. e) What are 2 properties that are different between the R and S enantiomer.A solution is prepared by mixing 5 mL of a 0.20 M solution of the S enantiomer of a compound and 10 mL of a 0.20 M solution of the R enantiomer. The specific rotation of that solution was -7.00. a.) Calculate the millimoles of each enantiomer in the mixture.b.) Calculate the% enantiomer in excess (% e.e).c.) Calculate the specific rotation of each pure enantiomer.
- 1. A solution has 80% (R)-2-bromobutane and 20% (S)-2-bromobutanea. What is the “enantiomeric excess” of (R)-2-bromobutane? b. If pure (R)-2-bromobutane rotates light 100º to the right, how much rotation would occur for a solution with 80% (R)-2-bromobutane and 20% (S)-2-bromobutane c. If a solution has a 50/50 mixture of (R)- and (S)-2-bromobutane, what would be the enantiomeric excess and the optical purity? 2. A mixture of two enantiomers has as observed rotation of -18°. The specific rotation of the (-) enantiomers is -27°. Find the % of the two enantiomers in the solution.b) A synthetic sample of MSG (conc 0.350 g/mL) is found to be a mixture of two enantiomers. What is the percentage of each enantiomer in the sample if the experimental rotation of the sample is found to be -2.15°?Consider a solution that contains 69.0% R isomer and 31.0% S isomer. If the observed specific rotation of the mixture is -58.0°, what is the specific rotation of the pure R isomer? [a] =
- If the sample of the pure R enantiomer of a molecule has a specific rotation of -40 degrees and your mixture of that molecule has an 82% ee S, what is the observed specific rotation of your sample?7.(a) Draw and label (a) the enantiomer and (b) a pair of diasteromers of the following compound. OH (c) Will a 50:50 mix of the enantiomers of the compound be optically active (rotate plane polarized light). Explain the reason for your answer d) Will a 50:50 mix of the two diasteriomers you drew in (c) be optically active (rotate plane polarized light). Explain the reason for your answer1. How can the chirality of compound 1? 2. How the configuration inversion of -OH moiety of compound 2 occur stereoselectively? Thank you....