2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter30: Orbitals And Organic Chemistry: Pericyclic Reactions
Section30.SE: Something Extra
Problem 37AP: The 1H NMR spectrum of bullvalene at 100 C consists only of a single peak at 4.22 . Explain.
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2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons
in the product and the # in the starting material tells us the # in the carbonyl. The fact that we
form only one product tells us the identity of the carbonyl.)
C8H9Br
1H NMR: 7.3-7.1 (m, 5H)
3.5 (t, 2H)
3.1 (t, 2H)
1) Ph3P
2) nBuLi
phosphonium ylide
carbonyl
C1114
(only one product formed)
Transcribed Image Text:2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)
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