2. Using conservation of energy, show that the speed v of an electron leaving your "electron gun" can be written in terms of the electron accelerating potential V, electron charge e and electron mass me as: v= 2eV me (5)

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2. Using conservation of energy, show that the speed v of an electron leaving your "electron gun" can be written
in terms of the electron accelerating potential V, electron charge e and electron mass me as:
v=
2eV
me
(5)
Transcribed Image Text:2. Using conservation of energy, show that the speed v of an electron leaving your "electron gun" can be written in terms of the electron accelerating potential V, electron charge e and electron mass me as: v= 2eV me (5)
be perpendicular to the electron velocity, causing the electrons to move in a circular path. By varying the current
going through the Helmholtz coils you will be able to vary the applied magnetic field and thus change the radius
of the electron paths. The magnetic field will be produced using "Helmhotlz coils" that produce a magnetic field
strength (at the center of the coil configuration) given by:
(4)
where R is the radius of the coils, N is the number of turns per coil (N = 124 in your set-up), Po=4π × 10-7 T· A/m,
and I is the current flowing though the coils.
Helium Filled
Vacuum tube
Electron Gun
(a)
Ve-
8 POIN
5√5 R
B =
electron's path
Deflection Plates
Grid.
Cathode.
Heater
•●●●●000
Anode
(b)
(+)
Deflection Plates
Figure 2: (a) Schematic diagram of the vacuum tube you will use to determine the value of e/me. The circular path of the
electron is shown in blue. Note the direction of the electron's velocity -. For the electron path shown here, the applied B
field points out of the page. (b) Cathode and anode arrangement of the electron gun in your apparatus.
Transcribed Image Text:be perpendicular to the electron velocity, causing the electrons to move in a circular path. By varying the current going through the Helmholtz coils you will be able to vary the applied magnetic field and thus change the radius of the electron paths. The magnetic field will be produced using "Helmhotlz coils" that produce a magnetic field strength (at the center of the coil configuration) given by: (4) where R is the radius of the coils, N is the number of turns per coil (N = 124 in your set-up), Po=4π × 10-7 T· A/m, and I is the current flowing though the coils. Helium Filled Vacuum tube Electron Gun (a) Ve- 8 POIN 5√5 R B = electron's path Deflection Plates Grid. Cathode. Heater •●●●●000 Anode (b) (+) Deflection Plates Figure 2: (a) Schematic diagram of the vacuum tube you will use to determine the value of e/me. The circular path of the electron is shown in blue. Note the direction of the electron's velocity -. For the electron path shown here, the applied B field points out of the page. (b) Cathode and anode arrangement of the electron gun in your apparatus.
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