2.3 Why is the Runge-Kuuta method more accurate compared to the Euler's
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A: Solution: a. From the given information, p=0.64 and n=50. For p-hat = 0.54. For p-hat = 0.61.
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- 8.5 q.4 part 2: Please fill in the blank box with the correct answer please, thank you.the answer is 5.41, would like to see how to get to it using Euler's methodCPUS made of two different materials are tested to see how they effect the processor speed of a computer. Specifically, material 1 is currently in use, but material 2 is acceptable. Since material 2 is cheaper, it should be adopted, providing it does not change the process yield. A test is run and results are obtained as follows. n = 8 n, = 8 81 2.39 82 2.98 X1 = 92.255 X2 = 92.733 Construct a 99% confidence interval for the difference of means under equal variance case.
- Does cell phone use while driving impair driver reaction times? At the Univ. of Utah the times (in milliseconds) of 32 drivers using cell phones to depress the brake pedal were compared to the reaction times of 32 drivers who were listening to the radio. For the cell phone users the results were = 585.2, s = 89.6; for the radio listeners the results were = 533.7, s = 65.3. Determine a 95% confidence interval for μ-μ where μ is the mean reaction for drivers using cell phones. Use df = 57.For a group of 20 items, EX=1452, X² = 144280 and mode = 63.7. Find the Pearsonian coefficient of skewness.Q.2. Because of potential variability in aging due to different castings and segments on the castings, a Latin square design with N=7 was used to investigate the effect of heat treatment on aging. With A= castings, B = Σχ = 297,216.90, segments, C = heat treatments, summary statistics include x... = 3815.8, Σχ = 297,155.01, and 297,200.64, = 297,317.65. Obtain the ANOVA table and test at level .05 the hypothesis that heat treatment has no effect on aging.
- A dietitian wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Five randomly selected subjects were pre-tested, and then they took the mineral supplement for a 6-week period. The Cholesterol level before and after taking the mineral supplements is shown in the table below. (Cholesterol level is measured in milligrams per deciliter). Table is attached Questions: If X1 is a normal variate with mean 2 and standard deviation 4 and X2 is a normal variate with mean 3 and standard deviation 9, then find E[X1 - 2X2] and Var(X1 - 2X2) The confidence level can be viewed as the amount of risk that an analyst will accept when making a decision (State True or False) You find a 90% confidence interval for true average thiamin content in oats for a given sample as (2.4,7.8) and you interpret the confidence interval as: I can be highly confident that 90% of the oats in the sample will have thiamin content between 2.4 and 7.8 (State True or…Find the coefficient of skewness using Karl-Pearson's and Bowley's.In the context of chi square, variables are independent if a. they are related b. cause and effect can be proved c. the obtained chi square falls in the critical region d. the score of a case on one variable has no effect on the score of the case on the other variable
- 1P Unit Four Assessment SPR 24(1) - Protected View Saved V gn Layout References Mailings Review View Help Search em the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected View. MAT 120: Unit Four Test Name: Enable Editing Be sure to give CLEAR answers with explanation where is it appropriate. If you write your answers and upload a photo of your test, make CERTAIN that it is a clear photo and your writing is legible. 1. Determine the critical value, Za/2, that corresponds to the given level of confidence. (3 points each) a. 90% b. 84% I 2. A Rasmussen Reports national survey of U.S. adults reported that 22% dreaded exercising. The margin of error in the survey was 3.7%. What is the confidence interval for the true proportion of adults who dreaded exercising in this situation? Just give the interval. (6 points) 3. In a USA Today/Gallup poll, 834 out of 1024 randomly selected adult Americans aged 18 or older stated that a candidate's positions on the…Suppose an animal scientist, Dr. Dew believes that birth weight (in kg) explains the variation in the length of gestation (in days until birth) for various mammals. To support this fact, he collected data and found out that when the birth weight was x = length of gestation was y = Hint: E;(xi – 2)² = 540, 916.8, E;(yi – 9)² = 195, 233, and E;(yi – ŷ)² = 181, 018. {60, 110, 44, 900, 107} the {122, 241, 61, 365, 617}. The fitted model was ĝ = 241.61+0.162x. a) Ignore the birth weight (x). If the length of gestation are independently and identically distributed (i.i.d.) with mean u and variance o?, what is the estimate for u and o?2, respectively? b) If you now use the birth weight (x) and assume that the length of gestation are (i.i.d.) with variance o? and mean µ = Bo + B1X. i) Compute the estimate for o?. (ii) By comparison to your estimate in part (a), what does this tell you about this model?The 98.6 degree standard for human body temperature was derived by a German doctor in 1868. In an attempt to verify his claim, Mackowiak, Wasserman, and Levine22 took temperatures from 148 healthy peopleover a 3-day period. A data set closely matching the one in Mackowiak’s article was derived by Allen Shoemaker, and appears in the Journal of Statistics Education.23 The body temperatures for these 130 individuals are shown in the relative frequency histogram that follows. See Attachment a. Describe the shape of the distribution of temperatures.b. Are there any unusual observations? Can you think of any explanation for these?c. Locate the 98.6-degree standard on the horizontal axis of the graph. Does it appear to be near the center of the distribution?