26 TH value cEAHo Fortle fermatien of phes pheres trichleride fremits censtituent elenen- P2G)t 3C12(9)→ 2pcl3 g) is-K)/mel A)-288-1 B) 432.4 1720S 0)-720.5 E)-432.4
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- c. For the reaction 2. CACO,(s) + 2H+ (aq)→ Ca (ag) + H,0(1) + CO, Species S J(mol K) CACO3 (s) 92.9 H* (ag) 0. Ca (aq) -53.1 H20(1) 69.95 CO, (9) 213.7 AS = JK•0= AG° + RT * In (K) %3D • -AG° = RT * In (K) %3D • AG° = -RT * In (K) %3D AG° = -0.616 * In (K)... %3D4 GIBBS ENERGY The following reaction happens in red blood cells CO2(g) + H2O (1) HCO3(aq) Using the following thermodynamic data (at 298.0 K) AH (kJ mol) 393.51 -285.83 CO2(g) H₂O (1) - CO (04) -699.65 Sm (IK 'mol) 213.7 69.9 187.4 (a) Calculate the standard entropy and the standard Gibbs energy of reaction at 298.0 K. Is the reaction exergonic or endergonic? (b) Using the Gibbs-Helmholtz equation, determine the standard Gibbs energy of the reaction at 310.0 K (37.0°C, body temperature). Notes Assume that the enthalpy of reaction does not change from 25.0°C to 37.0°C.
- 1. Calculate AH for the reaction: Use the following data: N₂ + O₂2NO 2NO N₂ + 0₂ 2NO+ O₂ → 2NO₂ Unit 7 - Worksheet 4: Hess's Law 2. Calculate AH for the reaction: Use the following data: required! C(graphite) + O₂ → CO₂ C(diamond) + O₂ → CO₂ Use the following data: 3. Calculate AH for the reaction: 2 Al + 1/2O₂ → Al2O3 N₂ + 20₂ >> 2NO₂ 2 Fe + 1½ 0₂ → Fe₂O3 C(graphite) → C (diamond) 2 Al + Fe₂O3 →2Fe + Bat Name: 00 AH = +180 kJ AH=-180kJ 012 Al₂O3 ΔΗ = - 112 kJ AH = - 394 kJ AH = -395 kJ AH = -1669 kJ AH = -824 kJFor the reaction below, formation salpies at 1 bar and standart entropies are given. Çe te equilibrium constant (Kp) of the reaction at 580 K. X(g) +3 Y,(g) =2XY,(g) For X,(g) AHº,f =0 kJ mol S° = 179 J mol* K For Y(g) AH°f = 0kJ mol* S° = 215 J mol"K** For XY,(g) AH°f = -146 kJ mol" S° = 154 mol K* R = 0.08206 L atm mol-1 K-1 = 8.314 J mol-1 K-1cal | YSU Question 4 - Chapter 19 - Conne x b Answered: .Which phase change x A ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=D0&launchUrl=https%253A%252F%252Fysu pter 19 Saved CuO(s) + H2(g) → Cu(s) + H2O() In this reaction, which substances are the oxidizing agent and reducing agent, respectively? oints Multiple Choice eBook References H2 and Cuo CuO and H2 Cu and H20 H20 and H2 CuO and Cu < Prev 4 of 10 Mc Graw Hill Type here to search
- A novel inorganic compound has two different crystalline forms, namely blue and red crystals. The physical and thermodynamic properties of blue and red crystals are given below. Mw of the novel inorganic compound is 86.54 g mol1. Properties (T = 298 K, P = 1.00 bar) Blue Red AH; (kJ mol 1) -1722.6 -1722.9 AG (KJ mol 1) -1648.5 -1647.1 Sin (U K1 mol 1) 86.4 81.2 CPm (JK1 mol 1) 66.5 65.7 Density (g mL 1) 2.145 2.278 What pressure must be achieved to induce the conversion of blue to red crystal at T = 298 K? Assume both blue and red crystals are incompressible at T = 298 K. Answer in bar to 0 decimal place (e.g. 1762).ll KKTCELL ? 12:01 PM @ 79% A moodle.ciu.edu.tr As a result of an experiment following measurements were obtained from a cell: ATP concentration of 10 mM, ADP concentration of 0.2 mM, inorganic phosphate (Pi) concentration of 0.5 mM. Under these conditions calculate the actual free energy (AG) of the reaction of hydrolysis of ATP to ADP and Pi. (The standard energy (AG°) of ATP = -31 kJ/mol; RT = 2.58 kJ/mol). Select one: O a. -33 kJ/mol O b. -19 kJ/mol c. -28 kJ/mol O d. -42 kJ/mol Next pageUse the following data, as appropriate, to estimate the molarity of a saturated aqueous solution of Sr(10s),- AH;. AGT. S kJ/mol kJ/mol Jmol-¹K-1 Sr(IO) ()-1019.2 855.1 234 Sr (aq) -545.8 -599.5 32.6 10₂(aq) -221.3 -128.0 118.4 Part A Molarity of a saturated aqueous solution of Sr(10₂) Express your answer to two significant figures with the appropriate units. C= Value Submit Request Answer Units ?
- For isobaric process, 1 mol of an ideal gas with Cp=5/2R the temperature changes from 125 K to 255 Kat a constant pressure of 10.0 atm. AH=-- 2700 kilo joul 2.7 kilo joul 1600 kilo joul O 1.6 joul 1.08 joul pH is- Ln[H+] log[H+] -log[H+] -log(H+) -In[H+]The table below provides data for the enthalpy and entropy of formation of compounds A and B at standard conditions (298 K) Compound DHfo (kJ mol-1) Sfo(J K-1mol-1) A –135.2 189.2 B –157.6 192.1 (b) A reversible isomerization reaction converts reactant A to product X. Calculate the Gibbs energy change at non-standard conditions (310 K) if the concentration of A is 2 x 10-4M and that of X is 3 x 10-6 M. Comment on whether the reaction is spontaneous at these conditions. The equilibrium constant Keq = 0.05. Assume standard temperature is 298K.a. Calculate the Gibbs energy of formation for a generic compound AB2 in kJ/mol given the following thermodynamic data A;H° kJ/mol S; J/mol K A(I) B2(g) AB2(s) 76.02 223.07 |-224.3 146.00 b. Interpret your result from part a. Will the formation of AB2(s) occur under standard state conditions? Why or why not?