2Fe2O3(s) 4Fe(s) + 302(g). Use the following data: So Fe(s) = 27.31 J/K, S° O2(g) = 205.15 J/K, S° Fe2O3(s) = 89.96 J/K. Express your answer in joules per kelvin to two decimal places. ΜΕ ΑΣΦ AS = 468.4 ? J/K
2Fe2O3(s) 4Fe(s) + 302(g). Use the following data: So Fe(s) = 27.31 J/K, S° O2(g) = 205.15 J/K, S° Fe2O3(s) = 89.96 J/K. Express your answer in joules per kelvin to two decimal places. ΜΕ ΑΣΦ AS = 468.4 ? J/K
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.34QE
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![2Fe2O3(s)
4Fe(s) + 302(g).
Use the following data: So Fe(s) = 27.31 J/K, S° O2(g) = 205.15 J/K, S° Fe2O3(s) = 89.96 J/K.
Express your answer in joules per kelvin to two decimal places.
ΜΕ ΑΣΦ
AS = 468.4
?
J/K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73b54b2c-e9d1-42e7-bdad-65fe9c402031%2F5cb10b32-81f3-4a39-98b3-7ddf784897e9%2Fv9btdk_processed.png&w=3840&q=75)
Transcribed Image Text:2Fe2O3(s)
4Fe(s) + 302(g).
Use the following data: So Fe(s) = 27.31 J/K, S° O2(g) = 205.15 J/K, S° Fe2O3(s) = 89.96 J/K.
Express your answer in joules per kelvin to two decimal places.
ΜΕ ΑΣΦ
AS = 468.4
?
J/K
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