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2m w.t. Cu 35 kN/m? Ye = 17.8 kn/m3 O' = 0° LL = 55, PL = 32 %3D Cu = 35 kN/m? Yi = 18.0 kn/m3 O' = 0° LL = 55, PL = 32 B=0.22 %3D 6m a=0.70 %3D 2=0.15 Cu = 45 kN/m² Yt = 18.3 kn/m3 O' = 0° LL = 52, PL = 34 20m %3D B-0.27 a-0.75 10m 2-0.18 Cu = 50 kN/m2 Yt = 18.5 kn/m3 O' = 0° LL = 50, PL = 38 B-0,32 a=0.90 =0.20 2m %3D %3D %3D

2m w.t. Cu 35 kN/m? Ye = 17.8 kn/m3 O' = 0° LL = 55, PL = 32 %3D Cu = 35 kN/m? Yi = 18.0 kn/m3 O' = 0° LL = 55, PL = 32 B=0.22 %3D 6m a=0.70 %3D 2=0.15 Cu = 45 kN/m² Yt = 18.3 kn/m3 O' = 0° LL = 52, PL = 34 20m %3D B-0.27 a-0.75 10m 2-0.18 Cu = 50 kN/m2 Yt = 18.5 kn/m3 O' = 0° LL = 50, PL = 38 B-0,32 a=0.90 =0.20 2m %3D %3D %3D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question

A 20m long steel pile with a 0.5m diameter is driven into layered clay soils as sown in the figure.

a) Calculate the end bearing capacity if Nc=8

b) Calculate the frictional resistance 

c) Calculate the allowable load if FS=3

2m w.t. Cu = 35 kN/m? Yi = 17.8 kn/m3 O' = 0° LL = 55, PL = 32 %3D Cu = 35 kN/m? Yt = 18.0 kn/m³ O' = 0° LL = 55, PL = 32 B=0.22 %3D 6m a=0.70 1-0.15 Cu = 45 kN/m² Yt = 18.3 kn/m3 o' = 0° LL = 52, PL = 34 20m B-0.27 q=0.75 10m 2-0.18 Cu = 50 kN/m² Yt = 18.5 kn/m³ o' = 0° LL = 50, PL = 38 B-0.32 a=0.90 -0.20 2m
Transcribed Image Text:2m w.t. Cu = 35 kN/m? Yi = 17.8 kn/m3 O' = 0° LL = 55, PL = 32 %3D Cu = 35 kN/m? Yt = 18.0 kn/m³ O' = 0° LL = 55, PL = 32 B=0.22 %3D 6m a=0.70 1-0.15 Cu = 45 kN/m² Yt = 18.3 kn/m3 o' = 0° LL = 52, PL = 34 20m B-0.27 q=0.75 10m 2-0.18 Cu = 50 kN/m² Yt = 18.5 kn/m³ o' = 0° LL = 50, PL = 38 B-0.32 a=0.90 -0.20 2m
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